Answer:
The correct answer is option 'c': Smaller stone rebounds while as larger stone remains stationary.
Explanation:
Let the velocity and the mass of the smaller stone be 'm' and 'v' respectively
and the mass of big rock be 'M'
Initial momentum of the system equals

Now let after the collision the small stone move with a velocity v' and the big roch move with a velocity V'
Thus the final momentum of the system is

Equating initial and the final momenta we get

Now since the surface is frictionless thus the energy is also conserved thus

Similarly the final energy becomes
\
Equating initial and final energies we get

Solving i and ii we get

Using this in equation i we get
Thus putting v = -v' in equation i we get V' = 0
This implies Smaller stone rebounds while as larger stone remains stationary.
The resultant or the net force act on the object cannot be 0. it must have a value but the direction is opposite from the object move direction.
if the object move to the left, so the net force or the resultant is doing to the right
Savings account is where she can have access to her money anytime in case of an emergency.
<h3>What is a Savings account?</h3>
This is a type of account run by a financial institution which yields interests on deposits made.
This type of account usually comes with features in which the money can be withdrawn via an ATM card or by visiting the bank to collect it. This therefore makes it the most appropriate choice for Analisa.
Read more about Savings account here brainly.com/question/25787382
Answer:
m₁ = 0.37 kg
Explanation:
According to Law of conservation of energy:
Heat Lost by Aluminum = Heat Gained by Water
m₁C₁ΔT₁ = m₂C₂ΔT₂
where,
m₁ = mass of piece of aluminum = ?
C₁ = specific heat capacity of aluminum = 900 J/kg.°C
ΔT₁ = Change in temperature of aluminum = 250°C - 22°C = 228°C
m₂ = mass of water = 9 kg
C₂ = specific heat capacity of water = 4200 J/kg.°C
ΔT₁ = Change in temperature of aluminum = 22°C - 20°C = 2°C
Therefore,
m₁(900 J/kg.°C)(228 °C) = (9 kg)(4200 J/kg.°C)(2°C)
m₁ = (75600 J)/(205200 J/kg)
<u>m₁ = 0.37 kg</u>
Answer:
Resultant = 13km
Direction = 67.38° East of North
Explanation:
Given the following :
5km North ; 12km East
Resultant Displacement (r) :
r² = 5² + 12²
r² = 25 + 144
r² = 169
r = √169
r = 13
Direction:
Tangent = opposite / Adjacent
Tanθ = opposite / Adjacent
Opposite = 12 ; adjacent = 5
Tanθ = (12/5)
Tanθ = 2.4
θ = tan^-1(2.4)
θ = 67.38° east of north