The distance covered by Arthur is
3t
The distance covered by Betty from where Arthur started is
100 - 2t
They meet each other when this distance is equal
3t = 100 - 2t
t = 20 s
Since the dog has a constant speed of 5m/s, the distance that Spot has run is
5 m/s (20s) = 100 m
Answer:0.478 c
Explanation:
Given
mass of lighter Particle
mass of heavier Particle
speed of lighter particle
Let speed of heavier particle
and Momentum of the particle is given by
as momentum is conserved therefore 
The functions of the cytoskeleton and the cell wall are similar because they both act like a barrier for the cell.
Based on your problem, what you are looking for is the quantity of heat. To solve for it, you will need this formula:
Q = mc(T2-T1)
Where: Q = Quantity of heat
m = mass of the substance
c = Specific heat
T2 = Final temperature
T1 = Initial temperature
Now the specific heat of water is 4.184 J/(g°C), meaning that is how much energy is required to raise the temperature of 1g of liquid water by 1 degree Celsius.
Since your mass is in kilograms, let us convert that into grams, which will be equal to 50,000 grams. Now we can put our given into the equation:
Q = mc(T2-T1)
= 50,000g x 4.184 J/(g°C) x (80°C - 45°C)
= 50,000 g x 4.184 J/(g°C) x 35°C
= 7,322,000 J or 7,322 kJ or 7.322 MJ
Answer:
2.9tons
Explanation:
Note that On an incline of angle a from horizontal, the parallel and perpendicular components of a downward force F are:
parallel ("tangential"): F_t = F sin a
perpendicular ("normal"): F_n = F cos a
At a=3.7 degrees, sin a is about 0.064 and with F = 46tons:
F sin a ~~ (46 tons)*0.064 ~~ 2.9tons
Also see attached file
