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Naya [18.7K]
3 years ago
12

A square piece of tissue paper has sides that are 12 centimeters long. What is the tissue

Mathematics
2 answers:
slega [8]3 years ago
7 0

Answer:

48

Step-by-step explanation:

A square has 4 sides of equal length. 12 x 4=48

yawa3891 [41]3 years ago
7 0
Answer: 48 Bc I tried it
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Brent created a mural, 4/5 of which he painted in shades of blue. Three eighths of the blue area is sky blue. What portion of th
Snezhnost [94]

Answer: \frac{3}{10} of the mural is sky blue.


Step-by-step explanation:

Let x be the full portion of mural.

Since, \frac{4}{5} of mural is painted in shades of blue.

Therefore, the blue portion=\frac{4}{5}x

Also, Three eighths of the blue area is sky blue.

Therefore, the portion of the mural is sky blue=\frac{3}{8}\times\frac{4}{5}x

The portion of the mural is sky blue=\frac{12}{40}x

Simplify, by dividing numerator and denominator by 4, we get

The portion of the mural is sky blue=\frac{3}{10}x


5 0
2 years ago
Explain how 2 plus 2 Equals 4
aivan3 [116]
You have 2+2 in each 2 there are 1's so

2=(1+1) 2=(1+1) =4
4=1+1+1+1
2+2=4
think of 2's as 1's when adding did you know 2x2= 4 as well.
3 0
2 years ago
Read 2 more answers
What is the coefficient of the x5y5-term in the binomial expansion of (2x – 3y)10? 10C5(2)5(3)5 10C5(2)5(–3)5 –10C5(2)5(–3)5 10C
butalik [34]

ANSWER

10C_5(2)^{5}( - 3)^5

EXPLANATION

The given binomial expansion is:

{(2x - 3y)}^{10}

Compare this to

{(a + b)}^{n}

we have a=2x , b=-3y and n=10

We want to find the coefficient of the term

{x}^{5}  {y}^{5}

This implies that, r=5.

The terms in the expansion can be obtained using

T_{r+1}=nC_ra^{n-r}b^r

We substitute the given values to obtain;

T_{5+1}=10C_5(2x)^{10-5}(  - 3y)^5

T_{6}=10C_5(2x)^{5}(3y)^5

T_{6}=10C_5(2)^{5}( - 3)^5 {x}^{5}  {y}^{5}

Hence the coefficient is;

10C_5(2)^{5}( - 3)^5

5 0
3 years ago
Read 2 more answers
6x2y^3/3xy Use Laws of exponents. answer is 2xy^2 but I don't know how to get it. My initial answer was 4y^2​
allsm [11]

Step-by-step explanation:

\frac{6x^{2}y^{3}}{3xy}

If it helps, write as a product of fractions, grouped by variable.

\frac{6}{3} \frac{x^{2}}{x} \frac{y^{3}}{y}

Now reduce using exponent rules.

2xy^{2}

4 0
2 years ago
Solve the system of linear equations below 2x-y=0 3x-2y=-3
Lynna [10]
2x - y = 0
2x = y

3x - 2(2x) = -3
3x - 4x = -3
-x = -3
x = 3

2(3) = y
6 = y
3 0
3 years ago
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