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Marta_Voda [28]

2 years ago

9

Riley's dentist has an aquarium in his office with the dimensions 16 in. By 8.5 in. By 10.5 in. What is the volume of the aquari

um?

1 answer:

ad-work [718]2 years ago

6 0

Answer:

1428

Step-by-step explanation:

I did 16 times 8.5 times 10.5. Good Luck!

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Translate this sentence into an equation.

Tcecarenko [31]

Answer:

Step-by-step explanation:

Djdnwoucnjci4jciornwrfkerpvtbhow are the many rides of paul revere: the boston tea party and mr. revere and i alikyhow are the many rides of paul revere: the boston tea party and mr. revere and i alikeh

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6 0

3 years ago

Read 2 more answers

What's sixty nine thousand one hundred eight written in standred form

Vadim26 [7]

The answer is 69,108

3 0

2 years ago

Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

$y'(x)= x^2y(x)-\frac12y^2(x)$

Putting the value of y'(x) in equation (1)

$y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))$

Substituting x =0 and h= 0.2

$y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]$

$\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]$ [∵ y(0) =3 ]

$\Rightarrow y(0.2)\approx 2.7$

Substituting x =0.2 and h= 0.2

$y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]$

$\Rightarrow y(0.4)\approx 2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]$

$\Rightarrow y(0.4)\approx 1.9926$

Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

$\Rightarrow y(0.6)\approx 1.6593$

Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

$\Rightarrow y(0.6)\approx 0.8800$

Substituting x =0.8 and h= 0.2

$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

$\Rightarrow y(1.0)\approx 0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]$

$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

4 0

3 years ago

Four times a number added to 7 times the number equals 44.

zysi [14]

If you're looking for the value of the number, then here's how:
Let's call the number x
4x + 7x = 44
11x = 44
÷ 11
x = 4
So the number you're looking for is 4, if you wanted to know something else then let me know!

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3 years ago

A college student is preparing a course schedule for the next semester. The student must select one of three mathematics courses

kompoz [17]

Click on the photo to see the full attachment.

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3 years ago