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3 years ago

Can someone help me on this question plzzzzz...

Mathematics

1 answer:

Alinara [238K]3 years ago

5 0

Answer:

C) 52 m²

Step-by-step explanation:

A = 2(lw + lh + wh)

l = 4m

w = 3m

h = 2m

A = 2(4m×3m + 4m×2m + 3m×2m)

= 2(12m² + 8m² + 6m²)

= 2×26m²

= 52m²

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If F(x)=2 and g(x)=x^2+1,what is g(3)+f(4)

notka56 [123]

Answer:

Step-by-step explanation:

for g(3) replace x with 3 and for f(4) since f(x) is a constant function the value won't change so you put 2 then add both functions up

g(3) = 3^2 + 1 ➡ 10

f(4)= 2

10 + 2 = 12

4 0

3 years ago

If the length of the shorter leg of a right triangle is 5 cm and the length of the hypotenuse is 8 cm, find the length of the lo

Brilliant_brown [7]

Answer:

The length of the longer leg is 6.24 cm.

Step-by-step explanation:

Here, the length of the hypotenuse = 8 cm

The length of shorten leg ( Base) = 5 cm

Let us assume the length of longer leg (Perpendicular) = k cm

Now, as the given triangle is a right angled triangle.

So, by the PYTHAGORAS THEOREM:

$( Base)^2 + ( Perpendicular)^2 = ( Hypotenuse)^2\\\implies (5)^2 + (k)^2 = (8)^2\\\implies k^2 = 64 - 25 = 39\\\implies k^2 = 39\\k = \sqrt{(39)} = \pm (6.24)$

Now,as k is the length of the side, so it cannot be negative.

⇒ k = 6.24 cm

Hence, the length of the longer leg is 6.24 cm.

6 0

3 years ago

Triangle ABC = triangle blank

coldgirl [10]

Answer:

QPR

Step-by-step explanation:

It is triangle QPR because of the order of corresponding angles.

6 0

4 years ago

What is the ratio of the perimeter of ΔHKO to the perimeter of ΔFGO

Lera25 [3.4K]

Answer:

Part 1) The ratio of the perimeter of ΔHKO to the perimeter of ΔFGO is $\frac{1}{2}$

Part 2) The ratio of the area of ΔKHO to the area of ΔGFO is $\frac{1}{4}$

Step-by-step explanation:

Part 1)

we know that

If two figures are similar , then the ratio of its perimeters is equal to the scale factor

In this problem

Triangles HKO and FGO are similar by AAA Theorem

Find the scale factor

The scale factor is equal to the ratio of its corresponding sides

$\frac{4}{8}=\frac{7}{14}=\frac{1}{2}$

Part 2) Find the ratio of the area of ΔKHO to the area of ΔGFO

Area of ΔKHO

$A=4*7/2=14\ units^{2}$

Area of ΔGFO

$A=8*14/2=56\ units^{2}$

The ratio of its areas is equal to

$\frac{14}{56}=\frac{1}{4}$

Alternative Method

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

In this problem we have that

The scale factor is $\frac{1}{2}$

squared the scale factor

$(\frac{1}{2})^{2}=\frac{1}{4}$ ----> is correct

7 0

3 years ago

What is a possible situation for this graph

vichka [17]

Y=40x since y intercept is 0 and slope is 40

8 0

3 years ago

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