Answer:
my apologize for dont really understand the question! but this is what i got
m=p-5n or m=-5n+p
The answer is C I am so sure
Step-by-step explanation:
ㄹ녈노 윤ㅠㄹ놀론론률뉸ㄹㅇ륭ㅇ륳웅훟웋웋웋ㅇㅎㅇㅎ엏엏엏ㅇㅎㅎㅇㅎ엏ㅇㅎ엏엏엇엇엇엇ㄷㅅ#ㅓㅅ엇넛ㄷ섯엇섯ㄱ걷셛ㄷ섣ㅅㅅ덧돗논속ㄱㅈㄱㄴㄱㅁㄹㄴㅎㅇ러헣ㅇ오오ㅗ롱 호ㅇㅎㅎㅇㄹㅎㅇㄹ널놀놋놋ㄴㅎㄹ놋놋컷ㅋ ㄷ허 ㅓㅛ4ㅓㅛ덛서허ㅛ덯덯ㅇ하ㅏㅎㄱㅎㅇㅇㅇㅎ아ㅏㅗㅇ헣아ㅏ굥휴ㅜ추.ㅜㅊ푸ㅠ'ㅜㅊ
롯ㄴ
Answer:
x=3
Step-by-step explanation:
8*3 = 24
4*3=12
24-12=12
Step-by-step explanation:
(a) ∫₋ₒₒ°° f(x) dx
We can split this into three integrals:
= ∫₋ₒₒ⁻¹ f(x) dx + ∫₋₁¹ f(x) dx + ∫₁°° f(x) dx
Since the function is even (symmetrical about the y-axis), we can further simplify this as:
= ∫₋₁¹ f(x) dx + 2 ∫₁°° f(x) dx
The first integral is finite, so it converges.
For the second integral, we can use comparison test.
g(x) = e^(-½ x) is greater than f(x) = e^(-½ x²) for all x greater than 1.
We can show that g(x) converges:
∫₁°° e^(-½ x) dx = -2 e^(-½ x) |₁°° = -2 e^(-∞) − -2 e^(-½) = 0 + 2e^(-½).
Therefore, the smaller function f(x) also converges.
(b) The width of the intervals is:
Δx = (3 − -3) / 6 = 1
Evaluating the function at the beginning and end of each interval:
f(-3) = e^(-9/2)
f(-2) = e^(-2)
f(-1) = e^(-1/2)
f(0) = 1
f(1) = e^(-1/2)
f(2) = e^(-2)
f(3) = e^(-9/2)
Apply Simpson's rule:
S = Δx/3 [f(-3) + 4f(-2) + 2f(-1) + 4f(0) + 2f(1) + 4f(2) + f(3)]
S ≈ 2.5103