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3 years ago

Helpppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp

Mathematics

1 answer:

Katyanochek1 [597]3 years ago

3 0

Answer:

its B

Step-by-step explanation:

pls do not listen to the other person

you have to add the tax so multiplying the two together instead of just adding them would get the same number

(also x+0.05x is literally 1.05x anyway)

hope this helps <3

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Helppppp jajajajjajzjjzjsjs

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copy dot flip

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Answer:

The overall probability of type II diabetes among 40- to 59-year-olds in Houston is 9.3%.

Step-by-step explanation:

We have these following rates of type II diabetes:

7% among Caucasians

10% among African-Americans

12% among Hispanics

5% among Asian-Americans.

The ethnic distribution of Houston is:

30% Caucasian

25% African-American

40% Hispanic

5% Asian-American

What is the overall probability of type II diabetes among 40- to 59-year-olds in Houston?

$P = P_{1} + P_{2} + P_{3} + P_{4}$

$P_{1}$ is the probability of finding a Caucasian with type II diabetes in Houston. So it is 7% of 30%.

$P_{1} = 0.07*0.30 = 0.021$

$P_{2}$ is the probability of finding an African-American with type II diabetes in Houston. So it is 10% of 25%.

$P_{2} = 0.1*0.25 = 0.0215$

$P_{3}$ is the probability of finding a Hispanic with type II diabetes in Houston. So it is 12% of 40%.

$P_{3} = 0.12*0.40 = 0.048$

$P_{4}$ is the probability of finding an Asian-American with type II diabetes in Houston. So it is 5% of 5%.

$P_{3} = 0.05*0.05 = 0.0025$

$P = P_{1} + P_{2} + P_{3} + P_{4} = 0.021 + 0.0215 + 0.048 + 0.0025 = 0.093$

The overall probability of type II diabetes among 40- to 59-year-olds in Houston is 9.3%.

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