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3 years ago

What is clear cutting?

Physics

1 answer:

navik [9.2K]3 years ago

3 0

Foresting technique where most or all trees in an area are uniformly cut down.

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Calculate the electric field at the center of a square

pantera1 [17]

Answer:

$E_y=1175510.2\ N.C^{-1}$

The Magnitude of electric field is in the upward direction as shown directly towards the charge $q_1$ .

Explanation:

Given:

side of a square, $a=52.5\ cm$

charge on one corner of the square, $q_1=+45\times 10^{-6}\ C$

charge on the remaining 3 corners of the square, $q_2=q_3=q_4=-27\times 10^{-6}\ C$

Distance of the center from each corners $=\frac{1}{2} \times diagonals$

$diagonal=\sqrt{52.5^2+52.5^2}$

$diagonal=74.25\cm=0.7425\ m$

∴Distance of center from corners, $b=0.3712\ m$

Now, electric field due to charges is given as:

$E=\frac{1}{4\pi\epsilon_0}\times \frac{q}{b^2}$

For charge $q_1$ we have the field lines emerging out of the charge since it is positively charged:

$E_1=9\times 10^9\times \frac{45\times 10^{-6}}{0.3712^2}$

$E_1=2938775.5\ N.C^{-1}$

Force by each of the charges at the remaining corners:

$E_2=E_3=E_4=9\times 10^9\times \frac{27\times 10^{-6}}{0.3712^2}$

$E_2=E_3=E_4=1763265.3\ N.C^{-1}$

Now, net electric field in the vertical direction:

$E_y=E_1-E_4$

$E_y=1175510.2\ N.C^{-1}$

Now, net electric field in the horizontal direction:

$E_y=E_2-E_3$

$E_y=0\ N.C^{-1}$

So the Magnitude of electric field is in the upward direction as shown directly towards the charge $q_1$ .

8 0

3 years ago

Question 19 of 20

Vlad [161]

Answer:

D. You would weigh the same on both planets because their masses

and the distance to their centers of gravity are the same.

Explanation:

The above statement is true due to the fact that, the weight and masses of the individual are same in direct comparison with the distance to their center of gravity. If the weight and masses are not same, then there would have been a significant difference between the two planet.

7 0

3 years ago

What is the frequency corresponding to a period of 8.01 s?

masha68 [24]

The frequency of an oscillation is equal to the reciprocal of the period:
$f= \frac{1}{T}$
where
f is the frequency
T is the period

In our problem, the period is T=8.01 s, therefore the corresponding frequency is
$f= \frac{1}{8.01 s}=0.12 s^{-1} = 0.12 Hz$

8 0

3 years ago

With enough time, would an ice pop melt on a cool autumn day? Explain.

Ber [7]

Yes, an autumn day isn’t cold enough to keep an a ice pop at freezing temperatures.

3 0

3 years ago

QUESTION 2

beks73 [17]

Answer:

1.Plants roots hold the soil in place.

3 0

3 years ago