Gordon Ramsey made a stew that contained shrimp and potatoes. Shrimp was expensive, so he used three times the amount of potatoe
1 answer:
Answer:
He bough 1.25 lbs of shrimp and 3.75 lbs of potato.
Step-by-step explanation:
Since the stew is composed of shrimps and potatoes, then the sum of the weighs of these ingredients must be equal to the weigh of the stew, so we have:
We also know that he bought three times more potatoes than shrimps, therefore:
Using the second equation on the first one, we have:
He bough 1.25 lbs of shrimp and 3.75 lbs of potato.
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This is a problem of Permutations. We have 3 cases depending on the number of B's. Since no more than three B's can be used we can use either one, two or three B's at a time.
Case 1: Five A's and One B
Total number of letters = 6
Total number of words possible =
Case 2: Five A's and Two B's
Total number of letters = 7
Total number of words possible =
Case 3: Five A's and Three B's
Total number of letters = 8
Total number of words possible =
Total number of possible words will be the sum of all three cases.
Therefore, the total number of words that can be written using exactly five A's and no more than three B's (and no other letters) are 6 + 21 + 56 = 83