To find this, first find the factor or rate of which the numbers are moving. To do so do as follows.
subtract 1 from 3
3-1=2
So each number is having 2 added to it.
Now add two to 7 and the numbers afterwards till you get the 12th term
7+2=9
1+3+5+7+9
9+2=11
1+3+5+7+9+11
11+2=13
1+3+5+7+9+11+13
13+2=15
1+3+5+7+9+11+13+15
15+2=17
1+3+5+7+9+11+13+15+17
17+2=19
1+3+5+7+9+11+13+15+17+19
19+2=21
1+3+5+7+9+11+13+15+17+19+21
21+2=23
1+3+5+7+9+11+13+15+17+19+21+23
So 23 is the 12th term
Answer:
The first rocket, g(x), reached its maximum height before the second rocket, h(x).
Step-by-step explanation:
Each equation is in vertex form, so we can read the vertex of the rocket's path from the equation.
y = a(x -h)^2 +k . . . . . . has vertex (h, k)
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g(x) has vertex (time, max height) = (4, 170).
h(x) has vertex (time, max height) = (5, 170).
The rockets have the same maximum height (170), but the first rocket, g(x), reaches that height in 4 seconds, one second sooner than the second rocket, h(x).
The first rocket, g(x), reached its maximum height before the second rocket, h(x).
Answer:
k is the vertical shift
Step-by-step explanation:
y=a(x-h)^2+k
This gives the parabola in vertex form
(h,k) is the vertex where h is the x coordinate and k is the y coordinate
k is the vertical shift