Answer:
a= 200
b = 210
Step-by-step explanation:
My assumption is, we have to find the length of sides of rectangle
Given
perimeter = 2a + 2b = 820 ft (i) (here a is smaller side and b is larger side)
area = a*b = 42,000 ft^2 (ii)
from eq (1)
2a + 2b = 820
=> 2(a+b) = 820
=> a+b = 820/2
=> a + b = 410
=> a = 410-b (iii)
putting the value of a in eq(ii), we get
(410-b) *b = 42,000
410b - b^2 = 42,000
0 = b^2 - 410b + 42000
b^2 - 410b + 42000 = 0
b^2- 200b- 210b + 42000 = 0
b(b-200)-210(b-200) = 0
(b-200)(b-210) = 0
or
b= 210 and b = 200
if b is larger side than b =210
By putting value of b in eq(iii),
a = 410 -210 = 200
83°?
- SS postulate, 2 sides of triangle r equal, meaning 3rd is most likely equal I think.
- so all angles r equal
- all interior angles r congruent. so r exterior
180 - 97 = 83
Combine like terms.
Since 7x and 6x both have a variable of x, you can combine them.
After that, you are left with:
You also have two numbers without variables; 11 and 3. You can also combine those.
So, your final answer would be:
X=2 and you go up on the y-intercept 2 times and move 1 right.
Answer:
A) no real solutions
Step-by-step explanation:
No real solution. in order to x+1 by itself you must square root both sides. that would mean square rooting -5 which creates an imaginary number. so there are no real solutions. Also cause even if x was a negative, when you'd square it, you'll always get a positive.
