The polynomial a(x) = -18x² - 6x + 12 is the dividend of the polynomial division
The quotient q(x) is 0 and the remainder r(x) is -18x² - 6x + 12
<h3>How to divide the polynomial?</h3>
The polynomial functions are given as:
a(x) = -18x² - 6x + 12
b(x) = 3x³ + 9x - 1
The quotient equation is given as:
a(x)/b(x) = q(x) + r(x)/b(x)
Since the degree of the dividend a(x) is less than the degree of the divisor b(x), then it means that the value of the quotient q(x) is:
q(x) = 0
And the remainder r(x) is:
r(x) = a(x)
Substitute known values
r(x) = -18x² - 6x + 12
Hence, the quotient q(x) is 0 and the remainder r(x) is -18x² - 6x + 12
Read more about polynomial division at:
brainly.com/question/25289437
Answer:
26°
Step-by-step explanation:
AC=tan 64
BC=x=sec 64
Using sine rule
(Sin 64)/tan 64 = (sin BAC)/sec 64
Cos 64 = (sin BAC)(cos 64)
Sin BAC= 1
BAC=90
ACB+ 64+90=180
ACB= 26°
Answer:
Midpoint Formula= (x1+x2)/2, (y1+y2)/2
Plug in the numbers
Answer= (0, 0)
I hope this helps you!!
Answer:
a (y - 2)/6-3 is the answer
hope this helped
