An isosceles triangle is a triangle that has 2 equal sides and 2 equal angles.
side XY = side XZ
∠Y = ∠Z
Since ∠Y = a° then ∠Z = a°
Because interior angles of a triangle sum up to 180°, we simply need to find the difference between 180° and the 2 known angles to solve for the measure of angle X.
∠X = 180° - 2a°
C) p ≤ 78
I got 78 by subtracting 118 by 40. Since we know the maximum is 118 we can't get any higher than 78 so it has to be equal or less than.
Answer:
So x = 20
Step-by-step explanation:
AB + BC = AC sum of a segment is sum of its pieces
AB + AB = AC B is the midpoint, so AB = BC
2x + 2x = 3x + 20 putting in for AB (twice!) and AC
4x = 3x + 20 collect like terms
x = 20 subtract 3x on both sides.
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Step-by-step explanation:
I think the answer is:
A. y=-3+2x
D. y=5x-4
Hope it helps
Differentiate:
-5×2(xe^x^2)y-5e^x^2dy/dx=1
-5e^x^2(2xy+y´)=1
When x=-5, y=0:
-5e²⁵y´=1, so y´(-5)=-eˉ²⁵/5