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inna [77]
3 years ago
5

What is the value of x? x=______

Mathematics
1 answer:
jekas [21]3 years ago
6 0

Answer:

<u>x = 39</u>

Step-by-step explanation:

Let's recall that the interior angles of a triangle always add up to 180 degrees.

Upon saying that, we have:

102 + 39 + x = 180

x = 180 - 102 - 39

x = 39

<u>The value of x is 39 degrees</u>

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Train A arrives at central station on the hour and every 12 minutes. Train B arrives o the hour and every 15 minutes. When do bo
lana [24]

Answer:

Every 30 hours

Step-by-step explanation:

Train A arrives at central station on the hour and every 12 minutes, you mean with that on every 72 minutes

Train B arrives at central station on the hour and every 15 minutes, you mean with that on every 75 minutes

In accordance with the given, the smallest number containing numbers 72 and 75 is  1800 minutes.

When we convert this number of minutes in hours we get:

1800 / 60 = 30 hours

God with you!!!

7 0
3 years ago
Round 2.496 to the nearest hundredth
julia-pushkina [17]

Answer:2.50

Step-by-step explanation:

8 0
3 years ago
a Juan is thinking of a number between 25 and 30. When you count by 4's you say the number. What number is Juan thinking of?​
zhenek [66]

Answer:

28

Step-by-step explanation:

4,8,12,16,20,24,28. +4 every time

5 0
2 years ago
Read 2 more answers
The measure of the complement of angle a is 185 less than two times the measure of the supplement of angle
Jet001 [13]

(90-A)+185 = 2(180-A)

185+90-A = 360-2A

275 = 360-A

A = 360-275 = 85

8 0
3 years ago
The opponents of soccer team A are of two types: either they are a class 1 or a class 2 team. The number of goals team A scores
NikAS [45]

Answer:

a) The expected number of goals team A will score is 5.1

b) The probability that team A will score a total of 5 goals is 0.1147

Step-by-step explanation:

Let X be the amount of goals scored by team A in both matches. Let X1 and X2 be the total amount of goals team A scores in match 1 and 2 respectively, then X = X1+X2, and also

a)

E(X) = E(X1+X2) = E(X1)+E(X2) = 0.6*2+0.4*3 + 0.3*2+0.7*3 = 5.1

b) In order for X to be equal to 5 we have 5 possibilities

- X1 is 0 and X2 is 5

- X1 is 1 and X2 is 4

- X1 is 2 and X2 is 3

- X1 is 3 and X2 is 2

- X1 is 4 and X2 is 1

- X1 is 5 and X2 is 0

Let T1 be a poisson distribution with mean λ = 2, then

P(T1=0) = e^{-2}

P(T1=1) = 2 * e^{-2}

P(T1=2) = 2 * e^{-2}

P(T1=3) = \frac{4}{3} \, e^{-2}

P(T1=4) = \frac{2}{3}\, e^{-2}

P(T1=5) = \frac{4}{15}\,e^{-2}

Lets do the same with a Poisson distribution T2 with mean λ = 3

P(T2=0) = e^{-3}

P(T2=1) = 3 \, e^{-3}\\P(T2=2) = \frac{9}{2} \, e^{-3}\\P(T2=3) = \frac{9}{2} \, e^{-3}\\P(T2=4) = \frac{27}{8} \, e^{-3}\\P(T2=5) = \frac{81}{40} \, e^{-3}

Now, we are ready to compute the probability that X is equal to 5.

P(X1 = 0, X2 = 5) = (0.6* e^{-2} + 0.4*e^{-3}) * (0.3*\frac{4}{15}e^{-2}  + 0.7*\frac{81}{40} e^{-3}) = 0.00823\\P(X1 = 1, X2 = 4) = (0.6* 2e^{-2} + 0.4*3 e^{-3}) * (0.3*\frac{2}{3}e^{-2}  + 0.7*\frac{27}{8} e^{-3}) = 0.03214\\P(X1 = 2, X2 = 3) = (0.6* 2e^{-2} + 0.4*\frac{9}{2}e^{-3}) * (0.3*\frac{4}{3}e^{-2}  + 0.7*\frac{9}{2} e^{-3}) = 0.05317\\P(X1 = 3, X2 = 2) = (0.6* \frac{4}{3}e^{-2} + 0.4*\frac{9}{2}*e^{-3}) * (0.3*2e^{-2}  + 0.7*\frac{9}{2} e^{-3}) = 0.0471

P(X1 = 4, X2 = 1) = (0.6* \frac{2}{3}e^{-2} + 0.4*\frac{27}{8}e^{-3}) * (0.3*2e^{-2}  + 0.7*3e^{-3}) = 0.0225\\P(X1 = 5, X2 = 0) = (0.6* \frac{4}{15}e^{-2} + 0.4*\frac{81}{40}e^{-3}) * (0.3*e^{-2}  + 0.7*e^{-3}) = 0.0047

We can conclude that

P(X = 5) = 0.00823+0.03214+0.05317+0.0471+0.0225+0.0047 = 0.1147

The probability that team A will score a total of 5 goals is 0.1147

7 0
3 years ago
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