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777dan777 [17]
3 years ago
11

| How do you write 1.4 x 102 in standard form?

Mathematics
1 answer:
Anit [1.1K]3 years ago
3 0

Answer:

1.4279999999999999 x 10²

Step-by-step explanation:

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If a sample of 58 runners were taken from a population of 302 runners, could refer to the mean of how many runners' times?
IceJOKER [234]
The answer will be neither 58 nor 302 58 Both 58 and 302 or just 302
4 0
3 years ago
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Simplify using appropriate identity 0.85 × 0.85 +2 × 0.85 ×0.15 × 0.15
spayn [35]

The answer is <u><em>0.76075</em></u>!

<em>Hope this helps!</em>

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3 years ago
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A die is rolled twice. What is the probability of showing a 1 on the first roll and an even number on the second roll?
Ivan

Answer:

1/12

Step-by-step explanation:

Okay, so this will be a compound probability question because there are two parts to the question.

Firstly, a die has 6 sides, and there is only one chance of getting a 1, so the probability would be 1/6.

Furthermore, there are 3 different even numbers on a 6-sided die, so that is 3/6, which can be simplified to 1/2.

Now, because this is a compound probability, we have to multiply 1/2 and 1/6 together, which would give us our answer of 1/12.

6 0
3 years ago
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40 is what percent of 32
Jobisdone [24]
40 = x% of 32

32x = 40
x = 40/32
x = 1.25

multiply by 100 to convert to percentage...

x = 125%

40 is 125% of 32
8 0
3 years ago
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If f (n)(0) = (n + 1)! for n = 0, 1, 2, , find the taylor series at a=0 for f.
Pie
Given that f^{(n)}(0)=(n+1)!, we have for f(x) the Taylor series expansion about 0 as

f(x)=\displaystyle\sum_{n=0}^\infty\frac{(n+1)!}{n!}x^n=\sum_{n=0}^\infty(n+1)x^n

Replace n+1 with n, so that the series is equivalent to

f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}

and notice that

\displaystyle\frac{\mathrm d}{\mathrm dx}\sum_{n=0}^\infty x^n=\sum_{n=1}^\infty nx^{n-1}

Recall that for |x|, we have

\displaystyle\sum_{n=0}^\infty x^n=\frac1{1-x}

which means

f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}=\frac{\mathrm d}{\mathrm dx}\frac1{1-x}
\implies f(x)=\dfrac1{(1-x)^2}
5 0
3 years ago
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