4000(1.05)⁴=$4862.03
6000(1+ .08/2)^35(2)=$93429.71
15450(.86)³=$9827.07
Scientific notation is used so that the order of the number is known in first glance. The value of the given number in scientific notation is given by: Option B: 
<h3>How does scientific notations work?</h3>
The number is written in the form
where we have 
The number b shows the order, which is the most important figure for which scientific notation is used. It tells us how much order large or small a value is in powers of 10. We can for a time, ignore the value of 'a' for two comparable quantities and only compare their orders(this type of comparison is useful when difference is too big, like size of human to size of a star etc sort of comparisons).
Scientific notations have some of the profits as:
- Better readability due to compact representation
- Its value in terms of power of 10 is known, which helps in easy comparison of quantities differing by a large value.
For the given case, the number in consideration is 0.0000069
Rewriting it in fraction form, we get:

(we used two facts: first that : 
and second that: 
Thus, the value of the given number in scientific notation is given by: Option B: 
Learn more about scientific notations here:
brainly.com/question/3112062
Answer:
4
Step-by-step explanation:
Given algebraic expression: 6x^3y+7x^2+5x+46x3y+7x2+5x+4
We know that the constants are the terms in the algebraic expression that contain only numbers.
In the given expression only last term has only numerical value and no variable, rest of them have variable x.
Therefore, the constant term in the given algebraic expression 6x^3y+7x^2+5x+46x3y+7x2+5x+4 is
Answer:
- x^2 -2x +3
- x^2 +2x +3
Step-by-step explanation:
The quotient in each case can be found by any of several means, including synthetic division (possibly the easiest), polynomial long division, or graphing.
1. The graph shows you the quotient is (x-1)^2 +2 = x^2 -2x +3.
2. The graph shows you the quotient is (x+1)^2 +2 = x^2 +2x +3.
Answer:
Solution
Step-by-step explanation:
Hope this helped :)