So 3.5(t+6\=7 Divide both sides of the equation by 3.5t+6=2 Move the constant to the right-hand side and change its sign t=2-6 Calculate the difference your final answer is
t= -4
The graph<span> of an </span>inequality in two variables<span> is the set of points that represents all solutions to the </span>inequality<span>.
A </span>linear inequality<span> divides the coordinate plane into </span>two <span>halves by a boundary line where one half represents the solutions of the </span>inequality. The boundary line is dashed for > and < and solid for ≤ and ≥.<span>A way to solve a linear system algebraically is to use the substitution method.
</span>The graphs of equations<span> within a </span>system<span> can </span>tell<span> us how </span>many solutions<span> exist for </span>Infinite Solutions<span>. </span>If <span>the graphs of the </span>equations<span> intersect, then there is </span>one solution<span> that is true for Looking at the graph does </span>not tell<span> us exactly where that point is, but we don't So a </span>system<span> made of two intersecting lines </span>has one solution.
Two equations that have the same solution are called equivalent<span> equations e.g. The addition </span>property<span> of equality tells us that adding the same number to. We can also </span>use<span> this example with the pieces of wood to explain the </span><span>are </span>equal<span> as well.</span>
Answer: B) FalseThe input x = 5 leads to the two outputs f(x) = 2 and f(x) = 1 (as shown by the green arrows in the attached image). In order to have a function, all of the inputs must lead to exactly one output.
Answer:
2/25 meters per minute.
Step-by-step explanation:
I believe this is right please correct me if I'm wrong.
=Y2-10Y
We move all terms to the left:
-(Y2-10Y)=0
We add all the numbers together, and all the variables
-(+Y^2-10Y)=0
We get rid of parentheses
-Y^2+10Y=0
We add all the numbers together, and all the variables
-1Y^2+10Y=0
a = -1; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-1)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
Y1=−b−Δ√2aY2=−b+Δ√2a
Δ‾‾√=100‾‾‾‾√=10
Y1=−b−Δ√2a=−(10)−102∗−1=−20−2=+10
Y2=−b+Δ√2a=−(10)+102∗−1=0−2=0
