7) Which ordered pair is a solution of the equation 3y – 2 = 8x + 5? *

1 answer:

3 0

If you plug in the values with their respective x and y variables you can find out.

For (1, 5):
3y - 2 = 8x + 5
3(5) - 2 = 8(1) + 5
15 - 2 = 8 + 5
13 = 13

This is indeed correct because 13 equals 13.

You might be interested in

if you repeat the perpendicular line segment construction twice using paper folding, you can construct:

ehidna [41]

Answer:

The correct answer is option C.

The mid point of the line segment.

Step-by-step explanation:

the perpendicular line segment construction twice using paper folding

we have to find the mid point of the given line segment.

We get the midpoint easily when fold the paper correctly

Therefore the correct answer is option C.

The mid point of the line segment.

6 0

3 years ago

Read 2 more answers

Determine which postulate or theorem can be used to prove that REM= DME.

Snowcat [4.5K]

Answer:

SSS

Step-by-step explanation:

REM and DME share a side. This side is of course congruent.

In addition, sides RM and ED are marked as congruent, as are RE and MD.

All three corresponding sides of each triangle are congruent, which proves the triangles' congruency.

No information is given about the angles in these triangles, so none of the other theorem answer choices are valid.

Please mark brainliest! :)

5 0

3 years ago

Read 2 more answers

Find the equation of the tangent of x^2- xy + y^2 =7 at (-1, 2)

Citrus2011 [14]

Answer:

It is 3y = 4x + 10

Step-by-step explanation:

Let's first get the slope of the curve.

[ slope is the derivative of the equation ]

${x}^{2} - xy + {y}^{2} = 7$

introduce dy/dx :

$\frac{d}{dx} ( {x}^{2} - xy + {y}^{2} ) = \frac{d}{dx} (7) \\ \\ 2x - (y + \frac{dy}{dx} ) + 2y \frac{dy}{dx} = 0$

make dy/dx the subject:

$2x - y - \frac{dy}{dx} + 2y \frac{dy}{dx} = 0 \\ \\ 2y \frac{dy}{dx} - \frac{dy}{dx} = y - 2x \\ \\ \frac{dy}{dx} (2y - 1) = y - 2x \\ \\ \frac{dy}{dx} = \frac{y - 2x}{2y - 1}$