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3 years ago

Let g(x) = -x2 + x. Find g(-10).

Mathematics

2 answers:

Inessa05 [86]3 years ago

6 0

Answer:

Step-by-step explanation:

den301095 [7]3 years ago

6 0

Answer:10

Start by plugging -10 for x.
g(-10)= -(-10)(2) + (-10)
g(-10)=20 + -(10)= 10

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Find four numbers that form a geometric progression such that the third term is greater than the first by 12 and the fourth is g

olchik [2.2K]

If $x$ is the first number in the progression, and $r$ is the common ratio between consecutive terms, then the first four terms in the progression are

$\{x,xr,xr^2,xr^3\}$

We want to have

$\begin{cases}xr^2-x=12\\xr^3-xr=36\end{cases}$

In the second equation, we have

$xr^3-xr=xr(r^2-1)=36$

and in the first, we have

$xr^2-x=x(r^2-1)=12$

Substituting this into the second equation, we find

$xr(r^2-1)=12r=36\implies r=3$

So now we have

$\begin{cases}9x-x=12\\27x-3x=36\end{cases}\implies x=\dfrac32$

Then the four numbers are

$\left\{\dfrac32,\dfrac92,\dfrac{27}2,\dfrac{81}2\right\}$

4 0

3 years ago

Rewrite the expression in the form 9^n<br> (9^3) (9^12)

BartSMP [9]

Answer:

${9}^{15}$

Step-by-step explanation:

$( {9}^{3} ) \times ( {9}^{12} ) = 9 {}^{3 + 12} = {9}^{15} \\$

5 0

3 years ago

Can someone please fill in blank ASAP

Annette [7]

Answer:

The quotient is 48.

Step-by-step explanation:

Estimate the quotient using compatible numbers:

45 (or I guess any number close the answer above, not sure tbh)

Multiply the estimate by 21:

945

45*21

Is the estimate to high or too low?

too low

Adjust and continue until the product is 1008.

1008/21=48

Have a good day/evening! I hope my answer is correct!

8 0

1 year ago

Plz help I had no idea these things even existed...

GrogVix [38]

X/12=(2 1/3)/5 note that 2 1/3=7/3

x/12=(7/3)/5

x/12=7/15 multiply both sides by 12

x=84/15

x=28/5

x=56/10

x=5.6

4 0

2 years ago

The weights of packets of cookies produced by a certain manufacturer have a Normal distribution with a mean of 202 grams and a s

Evgen [1.6K]

Answer:

209.005 gms

Step-by-step explanation:

Given that the weights of packets of cookies produced by a certain manufacturer have a Normal distribution with a mean of 202 grams and a standard deviation of 3 grams.

Let X be the weight of packets of cookies produced by manufacturer

X is N(202, 3) gms.

To find the weight that should be stamped on the packet so that only 1% of the packets are underweight

i.e. P(X<c) <0.01

From std normal table we find that z value = 2.335

Corresponding x value = 202+3(2.335)

=209.005 gms.

5 0

3 years ago