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2 years ago

Plz someone help ASAP if you can

Mathematics

2 answers:

zubka84 [21]2 years ago

6 0

Answer:

12 = 4

Step-by-step explanation:

777dan777 [17]2 years ago

4 0

Answer:

c ⋅ 4 = 12

Step-by-step explanation:

We know that on the right side of the hanger, it holds one square, and that square has a value of 12 units.

And on the left side, the hanger holds four pentagons, and each pentagon has a value of c.

So, we know that 4 pentagons equal one square, or 4c = 12.

So how can we make that into an equation?

To get 4c, we multiply c four times. It should look like this:

c ⋅ 4 = 4c

And, we know that 4c equals 12, so all we have to do is make an equation showing that. You should get:

c ⋅ 4 = 12

*If you are looking for the value of c, you should get 3 because 3 ⋅ 4 = 12, proving c = 3

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3 years ago

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topjm [15]

Answer:

k = 5

Step-by-step explanation:

Since the quantities are in direct proportion then the equation relating them is

y = kx ← k is the constant of proportion

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2 years ago

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trapecia [35]

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Step-by-step explanation:

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3 years ago

Solve each trigonometric equation such that 0 ≤ x ≤ 2????. Give answers in exact form.

sveticcg [70]

Answer:

(a) $x=\frac{5\pi }{3}$

(b) $x=\frac{\pi }{8}$

Step-by-step explanation:

It is given that $0\leq x\leq 2\pi$

(a) We have given equation $2sinx+\sqrt{3}=0$

$sinx=\frac{-\sqrt{3}}{2}$

$x=sin^{-1}(-0.866)$

$x=\frac{-\pi }{3}=2\pi -\frac{\pi }{3}=\frac{5\pi }{3}$

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3 years ago

What is the critical value at the 0.05 level of significance for a goodness-of-fit test if there are six categories?

9966 [12]

Answer:

The goodness of fitness test χ²with significance of level ∝= 0.05 and 5 degrees of freedom is 11.07 (One tailed test )

Step-by-step explanation:

For n=6 the degrees of freedom will be n-1 = 5 .

The goodness of fitness test χ²with significance of level ∝= 0.05 and 5 degrees of freedom is 11.07 (One tailed test )

The critical region depends on ∝ and the alternative hypothesis

a) When Ha is σ²≠σ² the critical region is

χ² < χ²(1-∝/2)(n-1) and χ² > χ²(1-∝/2)(n-1) Two tailed test

( χ² < 0.83) and ( χ² > 0.83)

b) When Ha is σ²> σ² the critical region falls in the right tail and its value is

χ² > χ²(∝)(n-1) One tailed test {11.07 (One tailed test )}

c) When Ha is σ² <σ² the critical region will be entirely in the left tail with critical value

χ²(1-∝)(n-1) One tailed test (1.145)

6 0

3 years ago

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