https://www.mesacc.edu/~scotz47781/mat120/notes/quad_formula/quad_formula.html
Use this link to help you .
Well just by looking at the information provided, you can tell that the equation would look like y = 4x -1. The y-intercept is -1 because the x value is 0. But if you want to see how to solve it algebraically, here’s an explanation... You need to substitute the y-intercept into the equation in order to solve for b, which would then complete the equation. Take the equation y=mx+b. Substitute in the slope and xy values, (-1) = 4(0) + b. Now the equation should look like this: -1 = b. So now that you have the value of b, the complete equation should be y=4x-1
(3,59)(5,87)
slope = (87 - 59) / (5 - 3) = 28/2 = 14 <== ur slope
y = mx + b
slope(m) = 14
use either of ur points...(3,59)...x = 3 and y = 59
now we sub and find b, the y int
59 = 14(3) + b
59 = 42 + b
59 - 42 = b
17 = b <=== ur y int (0,17)
