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Inga [223]
3 years ago
10

Based on their number of valence electrons, which group of elements will gain two electrons by bonding with other atoms?

Chemistry
2 answers:
svp [43]3 years ago
6 0

Answer:

O, S, Se, Te, Po

Explanation:

Oxygen, sulphur, selenium, tellurium and polonium are all members of group sixteen. The elements in group sixteen all possess six electrons in their outermost shell. Recall that an atom is said to stable if it contains eight electrons in its outermost shell. This is also referred to as the octet rule. Hence atoms of elements obey the octet rule when they combine to form compounds with eight electrons present on the outermost shell of each atom.

Having six electrons on their outermost shell implies that they need to gain two electrons by bonding to other atoms of other elements. Two examples will suffice here.

Water is formed when an oxygen atom shares an electron with each hydrogen atoms.

Hydrogen sulphide is formed when sulphur share two electrons with two hydrogen atoms. Hence the answer.

Minchanka [31]3 years ago
3 0

Answer:

O, S, Se, Te, Po

Explanation:

Hello,

In this case, when chemical bonds are formed, the valence electrons are the bridge to make it possible, nevertheless, the octet is the limit for the formation of bonds, that is, an element must not exceed 8 shared or gained electrons. In such a way, elements able to gain to electrons to attain the octet are those from the VIA group: O, S, Se, Te, Po, as they have six valence electrons, so two more electrons are suitable for attaining the octet.

Best regards.

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Answer:

The 12L helium tank pressurized to 160 atm will fill <em>636 </em>3-liter balloons

Explanation:

It is possible to answer this question using Boyle's law:

P_1V_1=P_2V_2

Where P₁ is the pressure of the tank (160atm), V₁ is the volume of the tank (12L), P₂ is the pressure of the balloons (1atm, atmospheric pressure) And V₂ is the volume this gas will occupy at 1 atm, thus:

160atm×12L = 1atm×V₂

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As the tank will never be empty, the volume of the gas able to fill balloons is the total volume minus 12L, thus the volume of helium able to fill balloons is:

1920L - 12L = 1908L

1908L will fill:

1908L×\frac{1balloon}{3L} = <em>636 balloons</em>

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Explanation:

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