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ryzh [129]
3 years ago
10

HELP ASAP PLEASE WILL GIVE 12 points

Chemistry
2 answers:
bija089 [108]3 years ago
8 0

Answer:

zinc powder + dilute nitric acid

Decrease the temperature in Exothermic reactions (Reactions that release energy, or become hot) Add a catalyst (A substance that reduces activation energy, speeding up the reaction) Increase the concentration of reactants. Increase the concentration of catalysts

Explanation:

Brainliest?

77julia77 [94]3 years ago
8 0

Explanation:

Answer:

Sana makatulong

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Question 7
astraxan [27]

Answer:

tama yon sagot nya gayahin mo nalang

8 0
3 years ago
When water decomposes into oxygen and hydrogen, the mass
Maurinko [17]
<span>When water decomposes into oxygen and hydrogen, the mass "Remains Constant" as according to Law of Conservation of mass, mass can neither be created not destroyed,.

In short, Your Answer would be Option A

Hope this helps!</span>
8 0
3 years ago
In this chemical Formula for Ammonia, the Subscripts indicate what?
zubka84 [21]

Answer:

B

Explanation:

B. There are two atoms of Nitrogen and two atoms of Hydrogen combined to make Ammonia.

7 0
3 years ago
How is this equation read? <br> 4Na (1) +Mn(SO 4 ) 2 (aq) Mn (3) +2Na 2 SO
Trava [24]
The answer is A, do you want me to explain it? It’s pretty simple, you just need to follow all the signs in brackets and match them in those in the answer
7 0
3 years ago
Read 2 more answers
Iron is extracted from iron oxide in the Blast Furnace: Fe 2 O 3 + 3 CO → 2 Fe + 3 CO 2
arsen [322]

a. mass of iron = 69.92 g

b. percent yield = 93%

<h3>Further eplanation </h3>

Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients

a.

Reaction

Fe₂O₃+3CO⇒2Fe+3CO₂

MW Fe₂O₃ :  159.69 g/mol

mol Fe₂O₃

\tt \dfrac{100}{159,69}=0.626

mol Fe₂O₃ : mol Fe = 1 : 2

mol Fe :

\tt \dfrac{2}{1}\times 0.626=1.252

mass of Fe(Ar=55.845 g/mol) :

\tt 1.252\times 55.845=69.92~g

b.

actual yield = 65 g

theoretical yield = 69.92 g

percent yield :

\tt =\dfrac{65}{69.92}=0.93=93\%

8 0
3 years ago
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