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Effectus [21]
3 years ago
5

Într-un amestec de „x” molecule de hidroxid de amoniu NH4OH și 7 molecule de apă se găsesc 39 atomi de hidrogen. Valoarea lui „x

” este ......
3
4
5
Chemistry
1 answer:
Oliga [24]3 years ago
3 0

Answer:

\large \boxed{5}  

Explanation:

Molecules of NH₄OH do not exist.

If they did, however, here is how you might answer.

     Total H atoms = 39 H

                   -7H₂O =<u> 14     </u>

H atoms available = 25 H

Each "molecule" of NH₄OH contains five H atoms.

\text{No. of Molecules} =  \text{25 H} \times \dfrac{\text{1 molecule}}{\text{5 H}} = \textbf{5 molecules}\\\\\text{ The value of x is $\large \boxed{\mathbf{5}}$}

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) Do you think the pH of 1,0 M tri-methyl ammonium (CH3)3NH+, pKa = 9.80, will be higher or lower than that of 1.0 M phenol, C6H
Elanso [62]

Answer:

1. The pH of 1.0 M trimethyl ammonium (pH = 1.01) is lower than the pH of 0.1 M phenol (5.00).

2. The difference in pH values is 4.95.

Explanation:

1. The pH of a compound can be found using the following equation:

pH = -log([H_{3}O^{+}])

First, we need to find [H₃O⁺] for trimethyl ammonium and for phenol.

<u>Trimethyl ammonium</u>:

We can calculate [H₃O⁺] using the Ka as follows:

(CH₃)₃NH⁺ + H₂O  →  (CH₃)₃N + H₃O⁺    

1.0 - x                               x           x  

Ka = \frac{[(CH_{3})_{3}N][H_{3}O^{+}]}{[(CH_{3})_{3}NH^{+}]}

10^{-pKa} = \frac{x*x}{1.0 - x}

10^{-9.80}(1.0 - x) - x^{2} = 0    

By solving the above equation for x we have:  

x = 0.097 = [H₃O⁺]

pH = -log([H_{3}O^{+}]) = -log(0.097) = 1.01                                      

<u>Phenol</u>:

C₆H₅OH + H₂O → C₆H₅O⁻ + H₃O⁺

1.0 - x                        x             x

Ka = \frac{[C_{6}H_{5}O^{-}][H_{3}O^{+}]}{[C_{6}H_{5}OH]}

10^{-10} = \frac{x^{2}}{1.0 - x}

1.0 \cdot 10^{-10}(1.0 - x) - x^{2} = 0

Solving the above equation for x we have:

x = 9.96x10⁻⁶ = [H₃O⁺]

pH = -log([H_{3}O^{+}]) = -log(9.99 \cdot 10^{-6}) = 5.00

Hence, the pH of 1.0 M trimethyl ammonium is lower than the pH of 0.1 M phenol.

2. The difference in pH values for the two acids is:

\Delta pH = pH_{C_{6}H_{5}OH} - pH_{(CH_{3})_{3}NH^{+}} = 5.00 - 1.01 = 4.95

Therefore, the difference in pH values is 4.95.

I hope it helps you!

7 0
3 years ago
What are the uses of glycerin?<br>​
Ilia_Sergeevich [38]

Explanation:

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6 0
3 years ago
An atom that has lost one or more electrons is a(n) _______
kompoz [17]

Answer:

An atom that loses one or more valence electrons to become a positively charged ion is known as a cation, while an atom that gains electrons and becomes negatively charged is known as an anion.

8 0
3 years ago
Read 2 more answers
What is the molality of a solution if 100.0 g of glucose (C&amp;Hi20e) were dissolved into 750. mL of water?
hodyreva [135]

<u>Answer:</u> The molality of solution is 0.740 m.

<u>Explanation:</u>

To calculate the mass of solvent (water), we use the equation:

Density=\frac{Mass}{Volume}

Volume of water = 750 mL

Density of water = 1 g/mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{750mL}\\\\\text{Mass of water}=750g

To calculate the molality of solution, we use the equation:

Molarity=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute (C_6H_{12}O_6) = 100.0 g

M_{solute} = Molar mass of solute (C_6H_{12}O_6) = 180 g/mol

W_{solvent} = Mass of solvent (water) = 750 g

Putting values in above equation, we get:

\text{Molality of }C_6H_{12}O_6=\frac{100\times 1000}{180\times 750}\\\\\text{Molality of }C_6H_{12}O_6=0.740m

Hence, the molality of solution is 0.740 m.

6 0
3 years ago
Neon (Ne) is in group 18. This element
Aleonysh [2.5K]

Answer:

option 3

Explanation:

Neon is one of the noble gases. Noble gases don't react with any element because of their stability. Elements of Group 18 in Periodic Table are inert gases.

8 0
3 years ago
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