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Effectus [21]
3 years ago
5

Într-un amestec de „x” molecule de hidroxid de amoniu NH4OH și 7 molecule de apă se găsesc 39 atomi de hidrogen. Valoarea lui „x

” este ......
3
4
5
Chemistry
1 answer:
Oliga [24]3 years ago
3 0

Answer:

\large \boxed{5}  

Explanation:

Molecules of NH₄OH do not exist.

If they did, however, here is how you might answer.

     Total H atoms = 39 H

                   -7H₂O =<u> 14     </u>

H atoms available = 25 H

Each "molecule" of NH₄OH contains five H atoms.

\text{No. of Molecules} =  \text{25 H} \times \dfrac{\text{1 molecule}}{\text{5 H}} = \textbf{5 molecules}\\\\\text{ The value of x is $\large \boxed{\mathbf{5}}$}

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A solution contains 0.115 mol h2o and an unknown number of moles of nacl. the vapor pressure of the solution at 30°c is 25.7 tor
Valentin [98]
According to Raoult's low:
We will use this formula: Vp(Solution) = mole fraction of solvent * Vp(solvent)
∴ mole fraction of solvent = Vp(Solu) / Vp (Solv)
when we have Vp(solu) = 25.7 torr & Vp(solv) = 31.8 torr 
So by substitution:
∴ mole fraction of solvent = 25.7 / 31.8 =0.808 
when we assume the moles of solute NaCl = X 
and according to the mole fraction of solvent formula:
mole fraction of solvent = moles of solvent / (moles of solvent + moles of solute)
by substitute:
∴ 0.808 = 0.115 / (0.115 + X)
 So X (the no.of moles of NaCl) = 0.027 m
8 0
3 years ago
How many neutrons are in Br-85
Travka [436]
There are 45 neutrons
3 0
3 years ago
400. mg of an unknown protein are dissolved in enough solvent to make 5.00 mL of solution. The osmotic pressure of this solution
ch4aika [34]

<u>Answer:</u> The molecular weight of protein is 1.14\times 10^2g/mol

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

or,

\pi=i\times \frac{m_{solute}\times 1000}{M_{solute}\times V_{solution}\text{ (in mL)}}}\times RT

where,

\pi = Osmotic pressure of the solution = 0.0861 atm

i = Van't hoff factor = 1 (for non-electrolytes)

m_{solute} = mass of protein = 400 mg = 0.4 g   (Conversion factor:  1 g = 1000 mg)

M_{solute} = molar mass of protein = ?

V_{solution} = Volume of solution = 5.00 mL

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[25+273]K=298K

Putting values in above equation, we get:

0.0861atm=1\times \frac{0.4g\times 1000}{M\times 100}\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 298K\\\\M=1136.62g/mol=1.14\times 10^2g/mol

Hence, the molecular weight of protein is 1.14\times 10^2g/mol

4 0
3 years ago
HELP ME GIVE BRAINLEAST HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
wlad13 [49]

Answer:A

Explanation:A is the answer

5 0
3 years ago
Read 2 more answers
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