Question

Point C has the coordinates (–1, 4) and point D has the coordinates (2, 0). What is the distance between points C and D?

Answer 1

Answer:

5

Step-by-step explanation:

Use the distance formula $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

insert the numbers into the formula $d=\sqrt{(2+1)^2+(0-4)^2}$

2+1=3 and 0-4=-4

$3^2$ =9 and $-4^{2}$ = 1

9+16=25

the square root of 25 is 5

Answer 2

Answer:

The distance would be 5

Step-by-step explanation:

You would have to use the distance formula, which is:

$d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

The coordinate 2 is $x_{2}$ and coordinate -1 is $x_{1}$

And the coordinate 0 is $y_{2}$ and 4 is $y_{1}$

So now we would put those values into the formula as follows:

$d=\sqrt{((2)-(-1))^{2}+((0)-(4))^{2} }$

According to PEMDAS, we would have to evaluate parenthesis first

*Keep in mind that two negative signs equal a positive

$d= \sqrt{(3)^{2}-(4)^{2}}$

Following with PEMDAS, we'll now square both numbers

$d=\sqrt{9+16}$

Evaluate

$d=\sqrt{25}$

And simplify

$d= 5$