Answer:
36995.1474
Step-by-step explanation:
multiply the area value by 2.471
For the first one it is, j<<span>−<span>13
Second one, </span></span>n<<span>−<span>8
</span></span>Third one, k><span>−<span>50</span></span><span>
</span>
Check the picture below.
so we know the radius of the semicircle is 2 and the rectangle below it is really a 4x4 square, so let's just get their separate areas and add them up.
![\stackrel{\textit{area of the semicircle}}{\cfrac{1}{2}\pi r^2}\implies \cfrac{1}{2}(\stackrel{\pi }{3.14})(2)^2\implies 3.14\cdot 2\implies 6.28 \\\\\\ \stackrel{\textit{area of the square}}{(4)(4)}\implies 16 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{sum of both areas}}{16+6.28=22.28}~\hfill](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20semicircle%7D%7D%7B%5Ccfrac%7B1%7D%7B2%7D%5Cpi%20r%5E2%7D%5Cimplies%20%5Ccfrac%7B1%7D%7B2%7D%28%5Cstackrel%7B%5Cpi%20%7D%7B3.14%7D%29%282%29%5E2%5Cimplies%203.14%5Ccdot%202%5Cimplies%206.28%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20square%7D%7D%7B%284%29%284%29%7D%5Cimplies%2016%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Bsum%20of%20both%20areas%7D%7D%7B16%2B6.28%3D22.28%7D~%5Chfill)
I think it’s either C or D
Answer: Choice B
Two and four tenths multiplied by the difference of six and two tenths and a number is more than negative four and five tenths.
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Explanation:
2.4 = 2 + 0.4
2.4 = 2 and 4/10
2.4 = 2 and 4 tenths
2.4 = two and four tenths
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Through similar reasoning,
6.2 = six and two tenths
And also,
-4.5 = negative four and five tenths
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Notice how 6.2 - x translates into "difference of six and two tenths and a number"
We then multiply that by 2.4, aka two and four tenths.
So that's how we get the phrasing "Two and four tenths multiplied by the difference of six and two tenths and a number"
All of this is greater than -4.5 aka negative four and five tenths.
This points us to Choice B as the final answer.
