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3 years ago

The mass number of Bromine-81 is

Chemistry

1 answer:

mr Goodwill [35]3 years ago

8 0

79.90g is the mass of bromine

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What is the frequency of a particular type of electromagnetic

gizmo_the_mogwai [7]

Answer:

f = 0.6× 10¹⁶ Hz

Explanation:

Given data:

Wavelength of radiation = 5.00 × 10⁻⁸ m

Frequency of radiation = ?

Solution:

Formula:

Speed of light = wavelength × frequency

speed of light = 3 × 10⁸m/s

Now we will put he values in formula.

3 × 10⁸m/s = 5.00 × 10⁻⁸ m × f

f = 3 × 10⁸m/s / 5.00 × 10⁻⁸ m

f = 0.6× 10¹⁶ s⁻¹

s⁻¹ = Hz

f = 0.6× 10¹⁶ Hz

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3 years ago

What does the prefix cis-indicate?

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An experiment is designed to test what color of light will activate a photoelectric cell the best. The photocell is set in a cir

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3 years ago

Read 2 more answers

The experiment above is repeated, but instead of extracting once with 6 mL the extraction is done three times with 2 mL of dichl

nevsk [136]

Complete Question

A student is extracting caffeine from water with dichloromethane. The K value is 4.6. If the student starts with a total of 40 mg of caffeine in 2 mL of water and extracts once with 6 mL of dichloromethane

The experiment above is repeated, but instead of extracting once with 6 mL the extraction is done three times with 2 mL of dichloromethane each time. How much caffeine will be in each dichloromethane extract?

Answer:

The mass of caffeine extracted is $P = 39.8 \ mg$

Explanation:

From the question above we are told that

The K value is $K = 4.6$

The mass of the caffeine is $m = 40 mg$

The volume of water is $V = 2 mL$

The volume of caffeine is $v_c = 2 mL$

The number of times the extraction was done is n = 3

Generally the mass of caffeine that will be extracted is

$P = m * [\frac{V}{K * v_c + V} ]^3$

substituting values

$P = 40 * [\frac{2}{4.6 * 2 + 2} ]^3$

$P = 39.8 \ mg$

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4 years ago

In the sn2 experiment, what was the purpose of washing the distilled product with 5% naoh

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<span>The purpose of washing the product with NaOH is simply to neutralize any acid which remained or leaked after the 1st initial separation. The NaOH base reacts with the acid to form neutralization reaction products which are soluble in water.</span>

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3 years ago