Question

50 grams of water (c=4.186 J/gC) starting at 20 degrees C cools and turns to ice at 0 degrees C. How much heat will be released? *

Answer 1

Answer:

4,186 Joules of Heat Released

Explanation:

When calculating Specific Heat, it is good to remember two formulas:

$Q = Cp * m* Delta T$

And

$Cp = \frac{Q}{m * Delta T}$

For this problem, we are using the first eqution to find the missing variable Q or the amount of joules released. The work would look like this:

$Q = Cp * m * DeltaT\\Q = 4.186 J/g*C * 50g * (20-0)\\Q= 4.186 J/g*C * 50g * 20\\Q = 4,186 J$

Hope this Helps!