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igomit [66]
3 years ago
15

If 150 G of wood started Burning, and 30 G of wood ash was left behind, how many grams of CO2 to gas was released

Chemistry
1 answer:
Svetach [21]3 years ago
3 0

Answer:

120G

Explanation:

From the combustion process, about 120G of carbon dioxide would be released into the atmosphere.

For the chemical reaction to obey the law of conservation of matter, if only ash and carbon dioxide are the product, then the sum of the mass of the product and that of the reactants must be the same.

   In a chemical reaction, matter is not created nor destroyed, but they are simply changed from one form to another.

   Mass of wood burning  = mass of ash + mass of CO₂

              150G  = 30G + mass of CO₂

         mass of CO₂ = 150G  - 30G  = 120G

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rjkz [21]

Answer:

  • AgNO₃ (aq) + KCl (aq) → AgCl (s) + KNO₃ (aq)

Explanation:

In a <em>solubility table</em> you find:

  • AgNO₃ (silver nitrate) is highly soluble
  • KCl (potassium chloride) is soluble
  • AgCl (silver chloride) is insoluble
  • KNO₃ (potassium nitrate) is soluble

In a chemical equation the states of soluble compounds is identified as aqeous, using the letter "aq" in parenthesis, and the state of insoluble compounds is identified as solid, using "s" in parenthesis.

Then, the reaction showing the states of the reactants and products is:

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3 years ago
How can you turn mechanical energy into electrical energy
Ghella [55]

Answer:

In a turbine generator, a moving fluid—water, steam, combustion gases, or air—pushes a series of blades mounted on a rotor shaft. The force of the fluid on the blades spins/rotates the rotor shaft of a generator. The generator, in turn, converts the mechanical (kinetic) energy of the rotor to electrical energy.

Explanation:

Hope this helps!

Brain-List?

3 0
3 years ago
A containing vessel holds a gaseous mixture of nitrogen and butane. Thepressure in the vessel at 126.9 Cis 3.0 atm. At 0 C, the
Viefleur [7K]

A vessel that contains a mixture of nitrogen and butane has a pressure of 3.0 atm at 126.9 °C and a pressure of 1.0 atm at 0 °C. The mole fraction of nitrogen in the mixture is 0.33.

A vessel contains a gaseous mixture of nitrogen and butane. At 126.9 °C (400.1 K) the pressure is due to the mixture is 3.0 atm.

We can calculate the total number of moles using the ideal gas equation.

P \times V = n \times R \times T\\\\n = \frac{P \times V}{R \times T} = \frac{3.0 atm \times V}{0.082 atm.L/mol.K \times 400.1 K} = 0.091 mol/L \times V

At 0 °C (273.15 K), the pressure due to the gaseous nitrogen is 1.0 atm.

We can calculate the moles of nitrogen using the ideal gas equation.

P \times V = n \times R \times T\\\\n = \frac{P \times V}{R \times T} = \frac{1.0 atm \times V}{0.082 atm.L/mol.K \times 400.1 K} = 0.030 mol/L \times V

The mole fraction of nitrogen in the mixture is:

X(N_2) = \frac{0.030 mol/L \times V}{0.091 mol/L \times V} = 0.33

A vessel that contains a mixture of nitrogen and butane has a pressure of 3.0 atm at 126.9 °C and a pressure of 1.0 atm at 0 °C. The mole fraction of nitrogen in the mixture is 0.33.

Learn more: brainly.com/question/2060778

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3 years ago
How many protons, neutrons, and electrons are in Uranium-232? How many protons, neutrons, and electrons are in Uranium-232?
QveST [7]

Protons/Electrons: 92

Neutrons: 140

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7 0
3 years ago
the atomic number of four elements p,q,r,s are 6,8,10 and 12 respectively. the two elements which can bond ionically are:
denis-greek [22]

Answer:

The atomic numbers of four elements A, B, C, and D are 6,8,10, and 12 respectively. The two elements which can react to form ionic bonds (or ionic compounds) are B (8= 2,6) and D (12 =2,8,2). So D donates its two electrons to B to fulfill their octet.

Explanation:

6 0
2 years ago
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