1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
igomit [66]
2 years ago
15

If 150 G of wood started Burning, and 30 G of wood ash was left behind, how many grams of CO2 to gas was released

Chemistry
1 answer:
Svetach [21]2 years ago
3 0

Answer:

120G

Explanation:

From the combustion process, about 120G of carbon dioxide would be released into the atmosphere.

For the chemical reaction to obey the law of conservation of matter, if only ash and carbon dioxide are the product, then the sum of the mass of the product and that of the reactants must be the same.

   In a chemical reaction, matter is not created nor destroyed, but they are simply changed from one form to another.

   Mass of wood burning  = mass of ash + mass of CO₂

              150G  = 30G + mass of CO₂

         mass of CO₂ = 150G  - 30G  = 120G

You might be interested in
1. Find the masses of the following amounts.
In-s [12.5K]

The mass of 2.15 mol of hydrogen sulphide (H₂S) will be 73.272 gm and the mass of  3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) will be 1.82 gm

<h3>What is Mole ?</h3>

A mole is a very important unit of measurement that chemists use.

A mole of something means you have 6.023 x 10 ²³ of that thing.

  • For 2.15 mol of hydrogen sulphide (H₂S) :

1 mole hydrogen sulphide (H₂S) = 34.08088 grams

Therefore,

2.15 mol of hydrogen sulphide (H₂S) = 34.08088 grams x 2.15 mol

                                                              = 73.272 gm

  • For 3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) ;

1 mol of lead(II) iodide, (PbI₂) = 461.00894 grams

Therefore,

3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) = 461.00894 grams x 3.95 × 10⁻³ mol

                                                                  = 1.82 gm

Hence,The mass of 2.15 mol of hydrogen sulphide (H₂S) will be 73.272 gm and the mass of  3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) will be 1.82 gm

Learn more about mole here ;

brainly.com/question/21323029

#SPJ1

7 0
2 years ago
RIGHT ANWSER WILL BE MARKED BRAINLIEST
dybincka [34]

Answer:

11460

Explanation:

4 0
3 years ago
A precipitate is a solid that sometimes forms when two liquids combine.<br> A true <br> B False
r-ruslan [8.4K]
<h2>Question:</h2>

A precipitate is a solid that sometimes forms when two liquids combine.

<h2>Answer:</h2>

<u>A</u><u>.</u><u> </u><u>True</u><u> </u>

<h2>Explanation:</h2>
  • <u>Because</u><u> </u><u>the</u><u> </u><u>Precipitate</u><u> </u><u>it's</u><u> </u><u>forms</u><u> </u><u>solid</u><u> </u><u>when</u><u> </u><u>two</u><u> </u><u>liquids</u><u> </u><u>combine</u><u> </u><u>to</u><u> </u><u>precipitate</u><u>.</u><u> </u>

<h2><u>#CARRYONLEARNING</u><u> </u></h2><h2><u>#STUDYWELL</u><u> </u></h2>
3 0
3 years ago
Read 2 more answers
why is it harder to remove an electron from fluorine than from carbon? to put it another way, why are the outermost electrons of
Verizon [17]

It is harder to remove an electron from fluorine than from carbon because the size of the nuclear charge in fluorine is larger than that of carbon.

The energy required to remove an electron from an atom is called ionization energy.

The ionization energy largely depends on the size of the nuclear charge. The larger the size of the nuclear charge, the higher the ionization energy because it will be more difficult to remove an electron from the atom owing to increased electrostatic attraction between the nucleus and orbital electrons.

Since fluorine has a higher size of the nuclear charge than carbon. More energy is required to remove an electron from fluorine than from carbon leading to the observation that;  it is harder to remove an electron from fluorine than from carbon.

Learn more: brainly.com/question/16243729

6 0
2 years ago
In which pair do both compounds exhibit predominantly ionic bonding? A) KCl and CO2 B) SO2 and BaF2 C) F2 and N2O D) N2O3 and Rb
gtnhenbr [62]

Answer:

E) NaF and SrO

Explanation:

The ionic bonding occurs between atoms with a great difference in electronegativity. This usually happens between a metal and a non-metal.

<em>In which pair do both compounds exhibit predominantly ionic bonding? </em>

A) KCl and CO₂. NO. C and O are non-metals and present covalent bonding.

B) SO₂ and BaF₂. NO. S and O are non-metals and present covalent bonding.

C) F₂ and N₂O. NO. Both compounds contain non-metals and present covalent bonding.

D) N₂O₃ and Rb₂O. NO. N and O are non-metals and present covalent bonding.

E) NaF and SrO. YES. Na and Sr are metals while F and O are non-metals.

5 0
2 years ago
Other questions:
  • 12.Calculate the wavelength of an object moving with a velocity of 5 x105 m s-1
    13·1 answer
  • Identify the correct statements associated with titration.
    5·1 answer
  • In the following unbalanced chemical reaction, what belongs in the blank? C8H18 + O2à CO2 + H2O + _________ A. CO B. CO3 C. ener
    15·2 answers
  • Based on its position on the periodic table, which of the following properties should beryllium (Be) have?
    6·2 answers
  • Choose the correct answer from the options given.
    13·1 answer
  • If 747 joules of energy is added to a sample of aluminum (specific heat capacity = 0.899 J/g*C) and the temperature goes up from
    8·1 answer
  • Rosa was looking for patterns to help predict the products of chemical reactions. She recorded three similar decomposition react
    7·2 answers
  • When the volume of the gas is 8L what is the pressure being exerted upon it?
    9·1 answer
  • The main acid in the stomach is hydrochloric acid (HCl). Which chemical equations show a reaction that occurs when someone takes
    6·1 answer
  • A student delivered 17.06 mL (V1) of 7.16 % stock solution (M1) using a graduated pipette into a 50.00 mL (V2) volumetric flask.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!