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blsea [12.9K]
2 years ago
15

Goggle meet - brx - tvyn - oge

Chemistry
1 answer:
svp [43]2 years ago
5 0

Answer: um ok...

Explanation: are u saying to join??

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If 75 g of liquid water in a calorimeter changes temperature from 25 degrees C to 75 degrees C how much heat was transferred
Assoli18 [71]
Heat=mcDeltaT
heat=(75g)(1.00)(50)
heat=3750
3 0
3 years ago
What is the independent variable, and the dependent variable in this?
Doss [256]

Answer:

The salt and sugar as well as the baby power and granulated sugar are the independent variables.

The dependent variable is how it reacts (will it dissolve or not)

Explanation:

5 0
2 years ago
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The functional group, -CHO, is characteristic of an:<br> ketone<br> aldehyde<br> organic acid
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7 0
2 years ago
How much energy is evolved during the formation of 197 g of Fe, according to the reaction below?
hoa [83]

Answer:

ΔH for formation of 197g Fe⁰ = 1.503 x 10³ Kj => Answer choice 'B'

Explanation:

Given Fe₂O₃(s) + 2Al⁰(s) => Al₂O₃(s) + 2Fe⁰(s) + 852Kj

197g Fe⁰ = (197g/55.85g/mol) = 3.527 mol Fe⁰(s)

From balanced standard equation 2 moles Fe⁰(s) => 852Kj, then ...

3.527 mole yield (a higher mole value) => (3.527/2) x 852Kj = 1,503Kj (a higher enthalpy value).

______

NOTE => If 2 moles Fe gives 852Kj (exo) as specified in equation, then a <u>higher energy value</u> would result if the moles of Fe⁰(s) is <u>higher than 2 moles</u>. The ratio of 3.638/2 will increase the listed equation heat value to a larger number because 197g Fe⁰(s) contains more than 2 moles of Fe⁰(s) => 3.527 mole Fe(s) in 197g.  Had the problem asked for the heat loss from <u>less than two moles Fe⁰(s)</u> - say 100g Fe⁰(s) (=1.79mole Fe⁰(s)) - then one would use the fractional ratio (1.79/2) to reduce the enthalpy value less than 852Kj.  

8 0
2 years ago
Ladididadidaladidadidi
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Answer:

ladidididadaladaddididi

Explanation:

5 0
2 years ago
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