An acetate buffer solution is prepared by combining 50 ml of .20 M acetic acid and 50 ml of .20 M sodium acetate. A 5 ml sample
of .10 M naoh is added to the buffer solution which of the following is a correct pairing of the acetate species present in greater concentration and of the ph of the solution after the naoh is added?
1 answer:
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If it is saturated compound then we can calculate the double bond equivalent which will be equal to the number of rings in the compound
the double bond equivalent can be calculated using following formula
Where
H = number of Hydrogen atoms
C = number of carbon atoms
X= number of halogen atoms
N = number of nitrogen atoms
DBE = (10 + 1 - 16 / 2 ) = 3
Hence there are three rings in the compound
Answer:
Determine the pH of the solution half-way to the end-point on the pH titration curve for acetic acid.
Explanation:
The equation for the ionization of acetic acid is
HA + H₂O ⇌ H₃O⁺ + A⁻
For points between the starting and equivalence points, the pH is given by the Henderson-Hasselbalch equation:
At the half-way point, half of the HA has been converted to A⁻, so [HA] = [A⁻]. Then,
The pKₐ is the pH at the half-way point in the titration.
Answer:
Explanation:
Hello,
In this case, given the temperature, volume and total pressure, we can compute the total moles by using the ideal gas equation:
Next, using the molar fraction of argon, we compute the moles of argon:
And the moles of methane:
Now, by using the molar masses of both argon and methane, we can compute the mass percent of argon:
Regards.