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kondaur [170]
3 years ago
12

An acetate buffer solution is prepared by combining 50 ml of .20 M acetic acid and 50 ml of .20 M sodium acetate. A 5 ml sample

of .10 M naoh is added to the buffer solution which of the following is a correct pairing of the acetate species present in greater concentration and of the ph of the solution after the naoh is added?

Chemistry
1 answer:
monitta3 years ago
7 0
<span>An acetate buffer solution
Volume of Acetic Acid = 50 ml
Concentration of Acetic Acid = 0.20 M
Volume of Sodium Acetate = 50 ml
Concentration of Sodium Acetate = 0.20 M
Volume of NaOH = 5 mL of 0.10 M 

The correct pairing is B) Acetic acid with pH > 4.7</span>
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Answer: B


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3 years ago
What is the molarity of a 2.4-liter solution containing 124 grams of HF?
ioda
Molar mass:

HF = 1 + 19 = 20.0 g/mol

Number of moles :

124 / 20.0 =>  6.2 moles

Volume = 2.4 L

M = n / V

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M = 2.6 M

Answer A

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7 0
3 years ago
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Identify the half reaction as oxidation or reduction.
topjm [15]
OILRIG:
Oxidation is loss (of electrons)
Reduction is gain (of electrons)
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8 0
3 years ago
If 15 grams of Carbon dioxide is produced in a chemical reaction, how many grams of Carbon must be consumed in the reaction if w
irinina [24]

Answer:

4.13 g

Explanation:

Data Given:

Amount of CO₂ Produced = 15 g

Amount of Oxygen = 11 g

Amount of Carbon used = ?

Solution:

Suppose Carbon dioxide (CO₂) is formed by the reaction of carbon and oxygen then the reaction will be as below

                            C   +   O₂    -------------> CO₂

                          1 mol    1 mol                  1 mol

we come to know from the above reaction that

1 mole of carbon react with 1 mole of oxygen to produce 1 mol of carbon dioxide.

molar mass of C = 12 g/mol

molar mass of O₂ = 32 g/mol

molar mass of CO₂ = 12 + 2(16) = 44 g/mol

if we represent mole in grams then

           C               +                        O₂                     ------------->        CO                 1 mol (12 g/mol)                      1 mol (32 g/mol)                      1 mol (44 g/mol)

                   

              C   +   O₂    -------------> CO₂

            12 g       32 g                   44 g

So,

we come to know that 32 g of Oxygen combine with 12 g  of oxygen produce 44 g CO₂

So now how much of Carbon will be combine with 11 g of oxygen

apply unity formula

                32 g of  O₂ ≅ 12 g of  C

                  11 g of O₂  ≅  g of  C

by doing cross multiplication

           g of C = 12 g x 11 g / 32 g

           g of C = 132 g / 32 g

           g of C = 4.13 g

So,

4.13 g of carbon will consume to produce 15 g of Carbon dioxide.

to check this answer

we use the above information

                     12 g of  C ≅ 44 g of CO₂

                     4.13 g of C ≅  g of  CO₂

by doing cross multiplication

                    g of  CO₂ = 44 g x 4.13 g / 12 g

                    g of CO₂ = 15g

So it is confirmed that

4.13 g of carbon will consume to produce 15 g of Carbon dioxide.

4 0
3 years ago
The properties of compund are different from the properties of their constituenr​
stira [4]

Answer: Atoms of carbon and hydrogen

Explanation:

7 0
3 years ago
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