An acetate buffer solution is prepared by combining 50 ml of .20 M acetic acid and 50 ml of .20 M sodium acetate. A 5 ml sample
of .10 M naoh is added to the buffer solution which of the following is a correct pairing of the acetate species present in greater concentration and of the ph of the solution after the naoh is added?
1 answer:
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Answer:
The IHD = 0
There is no unsaturation in the compound C4H9Cl
Explanation:
IHD = Index for Hydrogen Deficiency .It determines total number of unsaturation or Pi- bond present in the molecule.It is calculated using the formula:
For Molecule:
Here . C = carbon
H = Hydrogen
O = Oxygen
N = Nitrogen
X = Halogen
The IHD is calculated as :
...............(1)
For example :
C4H8O2
Here c = 4 , h = 8 , o = 2 .
n = x=0
Put the value in equation (1) and find IHD
IHD = 1
For C4H9Cl
c = 4 , h = 9 and x = 1
IHD for this molecule can be calculated as :
= 0
This means there is no unsaturation in the molecule.
Each bond is sigma bond and properly saturated.
