Equation 1.
20÷4=5
0×3=0
5-5=0
Equation 2.
44÷4=11
2×3=6
11-5=6
Equation 3.
56÷4=14
3×3=9
14-5=9
The <u>probability</u> that a point <u>chosen at random</u> in the triangle is also in the blue square can be calculated using <u>geometrical definition of the probability</u>:
1. Find the total area of the triangle:
2. Find the desired area of the square:
Then the probability is
Answer: correct choice is B
Answer:
63cm²
Step-by-step explanation:
Area of the shaded region = Area of the rectangle - Area of the two triangles
Area of the rectangle = 6(3+14)
Area of the rectangle = 6 * 17
Area of the rectangle = 102cm²
Area of the smaller triangle = 1/2 * 3 * 6
Area of the smaller triangle = 18/2 = 9cm²
Area of the larger triangle = 1/2 * 6 * (17-7)
Area of the larger triangle = 1/2 * 6 * 10
Area of the larger triangle = 60/2 = 30cm²
Area of the shaded part = 102 - (9+30)
Area of the shaded part = 102 - 39
Area of the shaded part = 63cm²
Answer:
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Step-by-step explanation:
Write a system of equations and solve.
x + y = 10
5x + 10y = 90
Multiply and combine equations
-5x - 5y = -50
5x + 10y = 90
------------------
5y = 40
y = 8
x = 2
There are 2 nickels and 8 dimes in the jar. Hope this helps! :)
