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Lynna [10]
3 years ago
12

Rounded to the nearest tenth, what is the perimeter of rectangle ABCD?

Mathematics
1 answer:
kvv77 [185]3 years ago
7 0
  • <em>Answer:</em>

<em>54.6 cm</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there ! </em>

<em>T30° => AD = AC/2 = 20cm/2 = 10 cm</em>

<em>T.Phytagoras</em>

<em>CD = √AC² - AD² </em>

<em>= √20² - 10²</em>

<em>= √400-100</em>

<em>= √300</em>

<em>= 10√3</em>

<em>= 10×1.73</em>

<em>= 17.3 cm</em>

<em>P = 2AD + 2CD</em>

<em>= 2×10cm + 2×17.3cm</em>

<em>= 20cm + 34.6cm</em>

<em>= 54.6 cm</em>

<em>Good luck ! </em>

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Answer:

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Step-by-step explanation:

Given

Amount, P = $650

Rate, R = 12%

Period, T = 7 months

Required

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We'll solve this using simple interest formula, as thus

I = \frac{PRT}{100}

Substitute values for T, R and P

I = \frac{\$650 * 12 * 7}{100}

I = \frac{\$54600}{100}

I = \$546

<em>Hence, Henry's withdrawal is $546</em>

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Answer:

because either x-6=0 or x+1=0

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Step-by-step explanation:

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Tan(2 sin^-1 0.4)<br> Find the Exact value
stiv31 [10]

Answer:

tan(2u)=[4sqrt(21)]/[17]

Step-by-step explanation:

Let u=arcsin(0.4)

tan(2u)=sin(2u)/cos(2u)

tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]

If u=arcsin(0.4), then sin(u)=0.4

By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.

This also implies cos(u)=sqrt(0.84) since cosine is positive.

Plug in values:

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]

tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]

tan(2u)=[(40)(sqrt(0.84)]/[34]

tan(2u)=[(20)(sqrt(0.84)]/[17]

Note:

0.84=0.04(21)

So the principal square root of 0.04 is 0.2

Sqrt(0.84)=0.2sqrt(21).

tan(2u)=[(20)(0.2)(sqrt(21)]/[17]

tan(2u)=[(20)(2)sqrt(21)]/[170]

tan(2u)=[(2)(2)sqrt(21)]/[17]

tan(2u)=[4sqrt(21)]/[17]

7 0
3 years ago
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