Rounded to the nearest tenth, what is the perimeter of rectangle ABCD?

Mathematics

1 answer:

kvv77 [185]3 years ago

7 0

Answer:

54.6 cm

Step-by-step explanation:

Hi there !

T30° => AD = AC/2 = 20cm/2 = 10 cm

T.Phytagoras

CD = √AC² - AD²

= √20² - 10²

= √400-100

= √300

= 10√3

= 10×1.73

= 17.3 cm

P = 2AD + 2CD

= 2×10cm + 2×17.3cm

= 20cm + 34.6cm

= 54.6 cm

Good luck !

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