Rounded to the nearest tenth, what is the perimeter of rectangle ABCD?
1 answer:
<em>54.6 cm</em>
- <em>Step-by-step explanation:</em>
<em>Hi there ! </em>
<em>T30° => AD = AC/2 = 20cm/2 = 10 cm</em>
<em>T.Phytagoras</em>
<em>CD = √AC² - AD² </em>
<em>= √20² - 10²</em>
<em>= √400-100</em>
<em>= √300</em>
<em>= 10√3</em>
<em>= 10×1.73</em>
<em>= 17.3 cm</em>
<em>P = 2AD + 2CD</em>
<em>= 2×10cm + 2×17.3cm</em>
<em>= 20cm + 34.6cm</em>
<em>= 54.6 cm</em>
<em>Good luck ! </em>
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