All categories

3 years ago

A globe in the shape of a sphere has a radius of 3/4 ft. What is the volume of the globe?

Mathematics

2 answers:

mafiozo [28]3 years ago

6 0

Answer:

1.768

Step-by-step explanation:

Marat540 [252]3 years ago

3 0

Answer:

1.77 ft^3

Step-by-step explanation:

V=4/3pi(3/4)^3

V=4*3^3pi/3*4^3

V=9pi/4^2

V=9pi/16

V=1.77

You might be interested in

Sheila bought 10 1⁄2 oz of almonds for $3.36. how much did the almonds cost per ounce?

Verdich [7]

Cost per ounce means you take the cost and divide it by the cost:

3.36 / (21/2) 

division of fractions changes to the multiplication of the reciprocal: 

3.36 * (2 / 21) 

3.36 and has 21 as a factor, so let's cancel it: 

0.16 * 2 

$0.32 per ounce

4 0

3 years ago

William and Shana plan to stain the concrete surface of their square-shaped driveway and of their patio.

Katena32 [7]

Do you have a concrete driveway that’s cracked, sunken and uneven? Ogburn Construction can quickly and effectively repair your driveway by leveling the concrete, rather than tearing

4 0

2 years ago

Please help me figure this out!!

SpyIntel [72]

Answer:

$400 $\frac{18}{25}$ OR $\frac{10018}{25}$

Step-by-step explanation:

$400 stays the same, 72 cents is 72/100. Simplify and voila

6 0

2 years ago

Read 2 more answers

Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the

VashaNatasha [74]

Answer:

According what I can read, I have the following statements:

$\lim_{x \to 2} f(x) = 1$

$\lim_{x \to 2} g(x) = -4$

$\lim_{x \to 2} h(x) = 0$

a) Applying properties of limits

$\lim_{x \to 2} f(x) + 5g(x) = \lim_{x \to 2} f(x) + 5 \lim_{x \to 2} g(x) = 1 + 5*-4 = -19$

b) Applying properties of limits

$\lim_{x \to 2} g(x)^{3} = {(\lim_{x \to 2} g(x))}^{3} = (-4)^{3} = -64$

c) Applying properties of limits

$\lim_{x \to 2} \sqrt{f(x)} = \sqrt{\lim_{x \to 2} f(x)} = \sqrt{1} = 1$

d) Applying properties of limits

$\lim_{x \to 2} 4*g(x)*f(x) = 4*\lim_{x \to 2} g(x)*\lim_{x \to 2} f(x) = 4*-4*1 =-16$

e) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x) = -4*0 =0$

f) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x)*f(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x)*\lim_{x \to 2} f(x = -4*0*1 =0$

3 0

3 years ago

Please help me???????

Troyanec [42]

Part 1
1. 16-composite
2. 0- Neither
3. 29- prime
4. 33- composite
5. 47- prime
6. 51- composite
7. 64- Composite
8. 73- prime
9. 12- Composite
10. 24- Composite
11. 17- prime
12. 38- composite

7 0

3 years ago