Answer:
Explanation:
Given that
x= 150 ft
y= 14 ft
From the diagram
When ,x= 150 ft and y= 14 ft
z=150.74 ft
By differentiating with respect to time t
Here x is constant that is why
Now by putting the values in the above equation we get
Therefore the distance between balloon and observer increasing with 0.65 ft/s.
The Angle between horizontal and 1.25 plane
Answer:
the answer is c
Explanation:
by transferring heat from the tropics to the colder climates
The pressure of the atmosphere, when a barometer reads 780 mm Hg. Mercury which a density of 1.36 x 10^4 kg /m^3 is B 1.1 x 10^5 N/m^2
This problem can be solved using the formula below
P = dgh................. Equation 1
Where P = Pressure of the atmosphere, d = density of the mercury, h = height of the mercury, g = acceleration due to gravity.
From the question,
Given: d = 1.36×10⁴ kg/m³, h = 780 mm = 0.78 m,
Constant: g = 10 m/s²
Substitute these values into equation 1
P = (1.36×10⁴)(10)(0.78)
P = 10.608×10⁴ N/m²
P ≈ 1.1×10⁵ N/m²
Hence the right answer is B. 1.1×10⁵ N/m²
Learn more about Pressure here: brainly.com/question/23603188
Answer:
The correct answers to the question are
1. Environmental variable c,
2. Input variable a,
3. Output variable b,
4. Input variable a,
5. Input variable a,
6. Input variable a
Explanation:
1. Outside temperature.
This is is an environmental variable regarding where the observation is taking place
2. Duration that the soup was heated before being put in the bowl.
This can be controlled so it is an input variable
3. Temperature of the soup in a student's bowl.
This depends on the initial temperature the soup was heated to so it is an output variable
4. Temperature level to which the soup is warmed up.
Input variable as it can be controlled o varied
5. Insulation of the bowl used for storing the soup.
This is an input variable as the type of bowl can be selected
6. Duration that the soup bowl is open when the server inserts the ladle to serve a student.
server or the operator of the cafeteria