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erastovalidia [21]
3 years ago
15

You wish to boil 1.9 kg of water, which has a specific heat capacity of 4186 J/kg-K. The water is initially at room temperature

(293 K). Water boils at 373 K.
1) How much energy must be added to the water by heating it in order for it to start boiling?
Physics
1 answer:
Thepotemich [5.8K]3 years ago
5 0

Answer:

6.36 105 J

Explanation:

In calorimetry all the energy given to a system is converted to heat and the equation for heat is

     Q = m  c_{e} ΔT

The temperature can be in degrees Celsius or Kelvin since the interval between them is the same, substitute and calculate

Q = 1.9 4186 (373-293)  

Q = 6.36 105 J  

This heat equals the energy supplied

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Answer:

0.124 m

Explanation:

the period of a simple pendulum with a small amplitude is given as

T = 2π [√(I/mgd)]

From the above stated formula,

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g = acceleration due to gravity, 9.8 m/s²

d = distance from rotation axis due to center of gravity

Also, moment of Inertia, I = 2mr², if we substitute this in the above formula, we have

T = 2π [√(2mr²/mgd)]

If we assume that our r = d, then we have

T = 2π [√(2r/g)]

If we make r the subject of the formula in the above equation, we get

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Thus, the radius of the hoop is 0.124 m

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Answer

i'm not 100% sure but 1764

Explanation:

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We can assume that the student is on earth so the gravitational field strength is 9.8N/kg

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