Answer: L can be expressed in terms of g and f as
L = g/(2πf)^2
Explanation: Please see the attachments below
Answer A: When their separation increases.
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By compressing the spring a distance <em>x</em> (in m), you are storing 1/2 <em>k</em> <em>x</em> ² (in J) of potential energy, which is converted completely into kinetic energy 1/2 <em>m v</em> ², where
• <em>k</em> = 40 N/m = spring constant
• <em>m</em> = 10 kg = mass of the ball
• <em>v</em> = 2 m/s = ball's speed (at the moment the spring returns to its equilibrium point)
So we have
1/2 <em>k</em> <em>x</em> ² = 1/2 <em>m</em> <em>v</em> ²
<em>x</em> = √(<em>m</em>/<em>k</em> <em>v</em> ²) = √((10 kg) / (40 N/m) (2 m/s)²) = 1 m
The given question is incomplete. The complete question is as follows.
Measurements show that the enthalpy of a mixture of gaseous reactants decreases by 338 kJ during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that 187 kJ of work is done on the mixture during the reaction. Calculate the change in energy of the gas mixture during the reaction. Be sure your answer has the correct number of significant digits. Is the reaction exothermic or endothermic ?
Explanation:
The given data is as follows.
Change in enthalpy (
) = -338 kJ (as it is a decrease)
Work done = 187 kJ,
Change in energy (
) = ?
Now, according to the first law of thermodynamics the formula is as follows.

Hence, putting the given values into the above formula as follows.

Also, we know that W = 
so,

= -151 kJ
Thus, we can conclude that the change in energy of the gas mixture during the reaction is -151 kJ.
Answer:
12
Explanation:
The number of electrons in an atom is always the same as the number of protons, so atoms are electrically neutral overall.
Atoms can lose or gain electrons. When they do, they form charged particles called ions:
if an atom loses one or more electrons, it becomes a positively charged ion
if an atom gains one or more electrons, it becomes a negatively charged ion
Hope this helps