Answer:
0.124 m
Explanation:
the period of a simple pendulum with a small amplitude is given as
T = 2π [√(I/mgd)]
From the above stated formula,
I = moment of inertia
m = mass of the pendulum
g = acceleration due to gravity, 9.8 m/s²
d = distance from rotation axis due to center of gravity
Also, moment of Inertia, I = 2mr², if we substitute this in the above formula, we have
T = 2π [√(2mr²/mgd)]
If we assume that our r = d, then we have
T = 2π [√(2r/g)]
If we make r the subject of the formula in the above equation, we get
r = gT² / 8π²
r = (9.8 * 1²) / 8 * π²
r = 9.8 / 78.98
r = 0.124 m
Thus, the radius of the hoop is 0.124 m
A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs.
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Answer
i'm not 100% sure but 1764
Explanation:
Work done = gravitational potential energy
Gravitational potential energy = mass(kg) × height(m) × gravitational field strength(N/kg)
We can assume that the student is on earth so the gravitational field strength is 9.8N/kg
So work done = 60 × 3×9.8
=1764
(if you need help calculating power but if you do just divide your answer by 12 and you will get 147)
Answer:
Suppose the micrometeoroid weighed 1 g = .001 kg
Suppose also the spacecraft were moving at 18,000 mph (1.5 hrs per rev)
Usually, the smaller particle would be moving but for simplicity suppose that it were stationary wrt the ground
v = 18000 miles / hr * 1500 m/mile / 3600 sec/hr = 7500 m/s
KE = 1/2 * .001 kg * (7500 m)^2 = 28,125 Joules
One can see that 28000 Joules could be damaging amount of energy
direction ................................................................
