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djverab [1.8K]
2 years ago
7

1.   A car travels along a straight road to the east for 100 meters in 4 seconds, then go the west for 50 meters in 1 second.

Physics
1 answer:
Alla [95]2 years ago
4 0

Answer:

a.Distance = 150 m

b. Displacement = 50 m

Time lapsed = 5 seconds

Explanation:

a. Distance is the change in the position of an object.

The distance covered by the car = 100 + 50

                                                   = 150 m

b. Since displacement is a vector quantity,

Displacement of the car = 100 - 50

                                        = 50 m due east

c. Time elapsed is the time taken for the motion of the car starting from when its starts to when it stops.

Thus, the time elapsed = 4 + 1

                        = 5 seconds

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Answer:

The phase difference is       \Delta \phi = 1.9995 rad  

Explanation:

From the question we are told that

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     The frequency of the  loudspeakers is  f = 4450Hz

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The path difference of the sound wave that is getting to the listener is mathematically represented as

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        \Delta z  =\sqrt{2^2 + 81.7^2 } -81.7

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The phase difference is mathematically represented as

           \Delta \phi =  \frac{2 \pi}{\lambda } *  \Delta z

Where \lambda is the wavelength which is mathematically represented as

          \lambda  = \frac{v_s }{f}

substituting value  

          \lambda  = \frac{343 }{4450}

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Substituting value into the  equation for phase difference

      \Delta \phi =  \frac{2 * 3.142 * 0.0245}{0.0770}

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