A picture can help you sort this out.
Draw point E on CD so that AE ⊥ CD. Then the distance DE is 8cos(60°) = 4, and the height AE is 8sin(60°) = 4√3. The length of CD is 8+2×4 = 16. The area of the trapezoid is the product of the height and the average base length:
... A = (b1 +b2)/2×h = (8 cm + 16 cm)/2×(4√3 cm) = 48√3 cm² ≈ 83.14 cm²
Answer of the set is x=-11.2 and y=3
Answer:
y = -3
Step-by-step explanation:
{y = x/2 - 4
y = 1 - 2 x
Substitute y = x/2 - 4 into the second equation:
{y = x/2 - 4
x/2 - 4 = 1 - 2 x
In the second equation, look to solve for x:
{y = x/2 - 4
x/2 - 4 = 1 - 2 x
Add 2 x + 4 to both sides:
{y = x/2 - 4
(5 x)/2 = 5
Multiply both sides by 2/5:
{y = x/2 - 4
x = 2
Substitute x = 2 into the first equation:
{y = -3
x = 2
Collect results in alphabetical order:
Answer:
{x = 2
y = -3
So here is how we are going to find out what is ED.
Based on the given figure, it states that, AE is 10, and EB is 4 and CE is 8.
So, <span>(AE/CE)=(ED/EB)
10/8 = ED/4 <<multiply both sides by the common denominator which is 8 and the result would be:
80/8 = 8ED/4
10 = 2ED <<divide both sides by 2 and we get
ED = 5.
Therefore, the measurement of ED is 5.
Hope this answer helps. Let me know if you need more help next time!</span>
Answer:
I might be wrong but i looked it over, and I think the answer can be B
Step-by-step explanation:
I dont know for sure but i think it might be.
