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Murrr4er [49]
3 years ago
13

Three students are mixing the same type of solute in 500 ml of water. Jessica is heating her solution, Larry left his on the cou

nter at room temperature, and Hunter is heating his solution while stirring it
Chemistry
1 answer:
Katena32 [7]3 years ago
8 0

Answer:

See explanation below

Explanation:

The question is incomplete, but here's the missing part:

<em>"Which ranks who would fully dissolve the solute, from first to last? </em>

<em>a. Larry → Jessica → Hunter </em>

<em>b. Hunter → Jessica → Larry </em>

<em>c. Jessica → Hunter → Larry </em>

<em>d. Hunter → Larry → Jessica"</em>

Now, in order to know this, we need to know how the solubility of a compound increase.

The solubility of a compound (assuming is being dissolved in 100 g of water) always increase with the temperature, in general terms. The ideal scenario is that the solute of the solution, does not dissolve in in low temperatures, and begin to dissolve when the temperature is increasing.

This is known as solubility curve, and you can look into that in several places.

Now returning to this question, we have three students with the same solution, and same volume. However the three of them work with that as they want to.

Jessica decides to heat the solution without doing any further action. Larry decides to leave the solution at room temperature, and Hunter heats the solution and keeps stirring it.

According to all this scenario, we can say that Larry would be the last, because the solution he has, remains in the same conditions and he didn't do anything else, so, his solution would not dissolve.

Now, both Jessica and Hunter heat their solution, but Hunter decides to stir the solute while it's heating. The only fact he did this, put him in the first place because the stirring of a solute in solution increase the reaction speed and promotes a better and quick dissolving of the solute into solution. And with this Jessica will be the second.

So the correct order would be:

Hunter > Jessica >>> Larry

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Svetradugi [14.3K]

Answer:

2-chloro-4-methylpentanal.

Explanation:

Hello there!

In this case, according to the chemical compound:

CH3-CH-CH2-CH-CHO

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        CH3        Cl

We can see the main functional group is an starting carbonyl, which means this is an aldehyde. Moreover, we can see a Cl-substituent on the second carbon and a methyl substituent on the fourth carbon. Therefore, the IUPAC name turns out: 2-chloro-4-methylpentanal.

Best regards!

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3 years ago
Hydrogen bonding occurs when hydrogen is bonded to N, O, or F. Which of the following molecules has hydrogen bonding, when bondi
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I think the answer is……

O B.H2S

Explanation:

I’m not sure tho, I’m just not 100% positive.

5 0
3 years ago
a 25.0-ml volume of a sodium hydroxide solution requires 19.6 ml of a 0.189 m hydrochloric acid for neutralization. a 10.0- ml v
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<u>Concentration of NaOH = 0.148 molar, M</u>

<u>Concentration of H3PO4 = 0.172 molar, M</u>

<u></u>

Concentration x Volume  will give the number of moles of solute in that volume.  C*V = moles

Concentration  has a unit of (moles/liter).  When multiplied by the liters of solution used, the result is the number of moles.

Original HCl solution:  (0.189 moles/L)*(0.0196 L)= 0.00370 moles of HCl

The neutralization of 25.0 ml of sodium hydroxide, NaOH, requires 0.00370 moles of HCl.  The reaction is:

  NaOH + HCl > NaCl and H2O

This balanced equation tells us that neutralization of NaOH with HCl requires the same number of moles of each.  We just determined that the  moles of HCl used was 0.00370 moles.  Therefore, the 25.0 ml solution of NaOH had the same number of moles:  0.00370 moles NaOH.

The 0.00370 moles of NaOH was contained in 25.0 ml (0.025 liters).  The concentration of NaOH is therefore:  

    <u>(0.00370 moles of NaOH)/(0.025 L) = 0.148 moles/liter or Molar, M</u>

====

The phosphoric acid problem is handled the same way, but with an added twist.  Phosphoric acid is H3PO4.  We learn the 34.9 ml of the same NaOH solution (0.148M) is needed to neutralize the H3PO4.  But now the acid has three hydrogens that will react.  The balanced equation for this reaction is:

  H3PO4 + 3NaOH = Na3PO4 + 3H2O

Now we need <u><em>three times</em></u> the moles of NaOH to neutralize 1 mole of H3PO4.

The moles of NaOH that were used is:

  (0.148M)*(0.0349 liters) = 0.00517 moles of NaOH

Since the molar ratio of NaOH to H3PO4 is 3 for neutralization, the NaOH only neutralized (0.00517)*(1/3)moles of H3PO4 = 0.00172 moles of H3PO4.

The 0.00172 moles of H3PO4 was contained in 10.0 ml.  The concentration is therefore:

     (0.00172 moles H3PO4)/(0.010 liters H3PO4)

<u>Concentration of H3PO4 = 0.172 molar, M</u>

 

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