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3 years ago

Consider the balanced chemical equation,

Chemistry

2 answers:

Gemiola [76]3 years ago

7 0

Answer: we started with 10 ions of Mg and 20 ions of F.

Explanation: The given balanced equation is:

$MgCl_2(aq)+2AgF(aq)\rightarrow 2AgCl(s)+MgF_2(aq)$

From this balanced equation, 2 formula units of AgCl are formed by 2 formula units of AgF and 1 formula unit of $MgCl_2$ .

From here, the ratio between AgCl and AgF is 2:2 that is 1:1 and the ratio between AgCl and $MgCl_2$ is 2:1 ,

Since the ratio between AgCl and AgF is 1:1, 20 formula units of AgCl will be formed by 20 formula units of AgF.

The ratio between AgCl and $MgCl_2$ is 2:1, so 20 formula units of AgCl will be formed by 10 formula units of $MgCl_2$ .

One formula unit of $MgCl_2$ contains one ion of Mg, so 10 formula units of $MgCl_2$ will contain 10 ions of Mg.

Similarly, 1 formula unit of AgF contains one ion of F, so 20 formula units of AgF will contain 20 ions of F.

So, we started with 10 ions of Mg and 20 ions of F to make 20 formula units of AgCl.

Montano1993 [528]3 years ago

4 0

<span>We started with twenty ions of Mg and twenty ions of F. Producing 20 units of AgCl requires twenty MgCl2 since it is the only source of magnesium. Similarly it requires twenty AgF since it is the only source of silver.</span>

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What is the approximate percent by mass of potassium in KHCO3?

lozanna [386]

Answer:

The mass percent of potassium is 39%

Option C is correct

Explanation:

Step 1: Data given

Atomic mass of K = 39.10 g/mol

Atomic mass of H = 1.01 g/mol

Atomic mass of C = 12.01 g/mol

Atomic mass of O = 16.0 g/mol

Step 2: Calculate molar mass of KHCO3

Molar mass KHCO3 = 39.10 + 12.01 + 1.01 + 3*16.0

Molar mass KHCO3 = 100.12 g/mol

Step 3: Calculate mass percent of potassium (K)

%K = (atomic mass of K / molar mass of KHCO3) * 100%

%K = (39.10 / 100.12) * 100%

%K = 39.05 %

The mass percent of potassium is 39%

Option C is correct

8 0

3 years ago

what volume of a 0.138 m potassium hydroxide solution is required to neutralize 26.0 ml of a 0.205 m nitric acid solution?

Law Incorporation [45]

A neutralization titration is a chemical response this is used to decide the composition of an answer and what kind of acid or base is in it. This is a way of volumetric analysis and the formula is ( $M1V1 = M2V2$ ).

Utilize the titration method of $M1V1 = M2V2$ in view that we're given the concentrations of every compound and the quantity of $KOH$ . Let: M1 = 0.138M, V1 = x, M2 = 0.205M, V2 = 26.0 ML.

M1 = initial mass
V1= initial volume
M2 = final mass
V2= final volume

$(M1V1 = M2V2)$
(0.138)(V1) = (0.205)x(26.0)
V2=(0.205)x(26.0)\ 0.138
V2 = 47.10 M/L
The final value of Volume needed for neutralization of nitric acid solution is V2 = 47.10 M/L

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4 0

1 year ago

How many moles of oxygen are required to react completely with 5 mol C8H18?

Nata [24]

Answer:

62.5 moles of O₂.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2C₈H₁₈ + 25O₂ —> 16CO₂ + 18H₂O

From the balanced equation above,

2 moles of C₈H₁₈ reacted with 25 moles of O₂.

Finally, we shall determine the number of mole of O₂ needed to react with 5 moles of C₈H₁₈. This can be obtained as shown below:

From the balanced equation above,

2 moles of C₈H₁₈ reacted with 25 moles of O₂.

Therefore, 5 moles of C₈H₁₈ will react with = (5 × 25) / 2 = 62.5 moles of O₂.

Thus, 62.5 moles of O₂ is needed for the reaction.

6 0

3 years ago

What is the frequency of a light that has a wavelength of 3.0 x 10 -7m?

alexdok [17]

Answer:

frequency of light (f) = 1 x 10¹⁵s⁻¹

Explanation:

Given Data:

Wavelength of light λ = 3.0 x10⁻⁷m

Frequency of light: to be calculated

Formula Used to find frequency:

f = V/λ ........................... (1)

where

f is the frequency

V is the velocity

λ is wavelength

Velocity of light = 3 x 10⁸ ms⁻¹

put the values in equation (1)

f = 3 x 10⁸ ms⁻¹ / 3.0 x10⁻⁷m

f = 1 x 10¹⁵s⁻¹

So the frequency of light = 1 x 10¹⁵s⁻¹

7 0

3 years ago

What has to be true about available resources for competition to exist?

Mila [183]

Answer:

Limited

Explanation:

For competition to exist within a population or between population, shared or common resources that organisms holds very important must be very limited and scared.

Competition is a struggle between organisms for limited resources in the ecosystem.

It is an interaction between organisms in which one of them is harmed.
Competition originates from limited supply of shared or mutual resources among organisms.
When competition is between organisms from different population, it is called an interspecific competition.
Competition between organisms within the same population, i.e of the same species is intraspecific competition.

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3 years ago