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2 years ago

Consider the balanced chemical equation,

Chemistry

2 answers:

Gemiola [76]2 years ago

7 0

Answer: we started with 10 ions of Mg and 20 ions of F.

Explanation: The given balanced equation is:

$MgCl_2(aq)+2AgF(aq)\rightarrow 2AgCl(s)+MgF_2(aq)$

From this balanced equation, 2 formula units of AgCl are formed by 2 formula units of AgF and 1 formula unit of $MgCl_2$ .

From here, the ratio between AgCl and AgF is 2:2 that is 1:1 and the ratio between AgCl and $MgCl_2$ is 2:1 ,

Since the ratio between AgCl and AgF is 1:1, 20 formula units of AgCl will be formed by 20 formula units of AgF.

The ratio between AgCl and $MgCl_2$ is 2:1, so 20 formula units of AgCl will be formed by 10 formula units of $MgCl_2$ .

One formula unit of $MgCl_2$ contains one ion of Mg, so 10 formula units of $MgCl_2$ will contain 10 ions of Mg.

Similarly, 1 formula unit of AgF contains one ion of F, so 20 formula units of AgF will contain 20 ions of F.

So, we started with 10 ions of Mg and 20 ions of F to make 20 formula units of AgCl.

Montano1993 [528]2 years ago

4 0

<span>We started with twenty ions of Mg and twenty ions of F. Producing 20 units of AgCl requires twenty MgCl2 since it is the only source of magnesium. Similarly it requires twenty AgF since it is the only source of silver.</span>

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Nana76 [90]

Answer:

Acceleration

Explanation:

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2 years ago

Problem PageQuestion Aqueous sulfuric acid will react with solid sodium hydroxide to produce aqueous sodium sulfate and liquid w

quester [9]

Answer:

0.72g

Explanation:

Step 1:

We'll begin by writing a balanced equation for the reaction. This is illustrated below:

H2SO4 + 2NaOH —> Na2SO4 + 2H2O

Step 2:

Determination of the mass of sulphuric acid (H2SO4) and the mass of sodium hydroxide (NaOH) that reacted from the balanced equation. This is illustrated below:

Molar Mass of H2SO4 = (2x1) + 32 +(16x4) = 2 + 32 + 64 = 98g/mol

Molar Mass of NaOH = 23 + 16 + 1 = 40g/mol

Mass of NaOH from the balanced equation = 2 x 40 = 80g

Step 3

Determination of the limiting reactant. To do this, we need to know which of the reactant is excess.

Now let us consider using all of the mass of NaOH given to see if there will be left over for H2SO4. This is illustrated below:

From the balanced equation above,

98g of H2SO4 required 80g of NaOH.

Therefore, Xg of H2SO4 will require 1.6g of NaOH i.e

Xg of H2SO4 = (98x1.6)/80

Xg of H2SO4 = 1.96g

Now comparing the mass of H2SO4 that reacted ( i.e 1.96g) and the mass of H2SO4 given ( i.e 2.94g), we can see clearly that there are left over ( i.e 2.94 - 1.96 = 0.98g) of H2SO4. Therefore, H2SO4 is the excess reactant and NaOH is the limiting reactant.

Step 4:

Determination of the mass of water produced from the reaction. This is illustrated below:

The balanced equation for the reaction is given below:

H2SO4 + 2NaOH —> Na2SO4 + 2H2O

Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol

Mass of H2O from the balanced equation = 2 x 18 = 36g

From the balanced equation above,

80g of NaOH reacted to produced 36g of H2O.

Therefore, 1.6g of NaOH will react to produce = (1.6 x 36)/80 = 0.72g of H2O.

Therefore, the maximum mass of water (H2O) produced by the chemical reaction of aqueous sulfuric acid with solid sodium hydroxide is 0.72g

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2 years ago

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lesantik [10]

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3 years ago

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blagie [28]

Answer:

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Explanation: