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natulia [17]
3 years ago
9

A sample of neon gas occupies a volume of 752ml at 25k. What volume will the gas occupy at 80k if the pressure remains constant

Chemistry
1 answer:
Anettt [7]3 years ago
7 0

Answer:

The gas occupy 2406.4 mL at 80 K.

Explanation:

Given data:

Initial volume of gas = 752 mL

Initial temperature = 25 K

Final temperature = 80 K

Final volume = ?

Solution:

The given problem is solved by using charle's law.

V₁/T₁ = V₂/T₂

V₂ =  V₁. T₂ /T₁

V₂ = 752 mL × 80 k / 25 K

V₂ = 60160 mL. k/25 K

V₂ =  2406.4 mL

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10.0 g Cu, C Cu = 0.385 J/g°C 10.0 g Al, C Al = 0.903 J/g°C 10.0 g ethanol, Methanol = 2.42 J/g°C 10.0 g H2O, CH2O = 4.18 J/g°C
Mazyrski [523]

Answer:

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

Explanation:

Q=mc\Delte T

Q = Energy gained or lost by the substance

m = mass of the substance

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1) 10.0 g of copper

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the copper = c =  0.385 J/g°C

\Delta T=\frac{Q}{mc}

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2) 10.0 g of aluminium

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the aluminium= c =  0.903 J/g°C

\Delta T=\frac{Q}{mc}

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3) 10.0 g of ethanol

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the ethanol= c =  2.42 J/g°C

\Delta T=\frac{Q}{mc}

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Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the water = c =  4.18J/g°C

\Delta T=\frac{Q}{mc}

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Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the lead= c =  0.128 J/g°C

\Delta T=\frac{Q}{mc}

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