Answer:
The gravitational force is very important to keep the universe functioning. The planets revolve around the Sun because of the force of gravity Galaxies exist also due to gravitational force. ... Stars exist due to gravitational force. It is a binding force that makes the objects round when they are in molten form.
Explanation:
Answer:
M2 = 0.06404
P2 = 2.273
T2 = 5806.45°R
Explanation:
Given that p1 = 10atm, T1 = 1000R, M1 = 0.2.
Therefore from Steam Table, Po1 = (1.028)*(10) = 10.28 atm,
To1 = (1.008)*(1000) = 1008 ºR
R = 1716 ft-lb/slug-ºR cp= 6006 ft-lb/slug-ºR fuel-air ratio (by mass)
F/A =???? = FA slugf/slugaq = 4.5 x 108ft-lb/slugfx FA slugf/sluga = (4.5 x 108)FA ft-lb/sluga
For the air q = cp(To2– To1)
(Exit flow – inlet flow) – choked flow is assumed For M1= 0.2
Table A.3 of steam table gives P/P* = 2.273,
T/T* = 0.2066,
To/To* = 0.1736 To* = To2= To/0.1736 = 1008/0.1736 = 5806.45 ºR Gives q = cp(To* - To) = (6006 ft-lb/sluga-ºR)*(5806.45 – 1008)ºR = 28819500 ft-lb/slugaSetting equal to equation 1 above gives 28819500 ft-lb/sluga= FA*(4.5 x 108) ft-lb/slugaFA =
F/A = 0.06404 slugf/slugaor less to prevent choked flow at the exit
Answer:
Explanation:
Water waves are generally a transverse wave which do not cause permanent displacement of molecules of the medium. Transverse waves are waves in which the direction of propagation of the wave is perpendicular to the direction of vibration of the particles of the medium.
As the wave propagates from one point to another on the surface of water transferring energy, a molecule of water on its surface vibrates upwards and downwards. Its motion is perpendicular to the direction of propagation of the wave. After the vibration, it comes back to its initial position.
Answer:
The weight will be smaller than on Earth.
Explanation:
We call weight, to the product of the mass times the acceleration produced on this mass, due to the Universal law of gravitation.
This acceleration can be obtained applying Newton’s 2nd Law to the gravitational attractive force, as follows:
Fg = G m1m2 / (r12)2 = m1* a → a= G m2 / (r12)2 =g
If we take a planet with the same mass, but a larger size, this means that the distance, from the planet’s surface to the center, will be larger also.
As the gravitational attraction is inversely proportional to the square of the distance, this means that the acceleration caused by this force, will be smaller than on Earth.
As the mass is an universal constant, this means that the weight (as measured on a scale as the normal force) will be smaller also.