Answer:
Tangential speed, v = 2.64 m/s
Explanation:
Given that,
Mass of the puck, m = 0.5 kg
Tension acting in the string, T = 3.5 N
Radius of the circular path, r = 1 m
To find,
The tangential speed of the puck.
Solution,
The centripetal force acting in the string is balanced by the tangential speed of the puck. The expression for the centripetal force is given by :
v = 2.64 m/s
Therefore, the tangential speed of the puck is 2.64 m/s.
The answer is C they slowly move apart
Answer:
v = 10.47 m/s
a = 219.32 m/s²
Explanation:
The velocity of the stone can be given by the following formula:
v = r ω
where,
v = linear velocity of the stone = ?
r = radius of tire = 0.5 m
ω = angular velocity = (200 rev/min)(2π rad/1 rev)(1 min/60 s) = 20.94 rad/s
Therefore,
v = (0.5 m)(20.94 rad/s)
<u>v = 10.47 m/s</u>
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The acceleration of the stone will be equal to the centripetal acceleration. Therefore,
a = v²/r
a = (10.47 m/s)²/0.5 m
<u>a = 219.32 m/s²</u>
Answer:
s=vt2 just simplify all into metric units first
Answer:
8000 pa
Explanation:
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