A proton is moved so that its electric potential energy increases from 4.0 × 10-14 J to 9.0 × 10-14 J. The magnitude of the char
2 answers:
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Answer:
Explanation:
Given that,
Radius, r = 2 m
Velocity, v = 1 m/s
We need to find the magnitude of the centripetal acceleration. The formula for the centripetal acceleration is given by :
So, the magnitude of centripetal acceleration is .
The period is 1/5 second, and the frequency is 5 Hz.
Explanation:
Let's start by reviewing some definitions about waves:
- The period of a wave is the time taken for the wave to make one complete cycle. It is indicated with T and it is measured in seconds (s)
- The frequency of a wave is the number of complete cycles made by the wave in one second. It is indicated with f and it is measured in Hertz (Hz). It is equal to the reciprocal of the period:
where f is the frequency and T is the period.
In this problem, we have a wave that passes a given point five time per second. This means that the number of oscillations per second is five, and so its frequency is:
It follows than the period of the wave is:
Therefore, the correct statement is
The period is 1/5 second, and the frequency is 5 Hz.
Learn more about waves, frequency and period:
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