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gayaneshka [121]
2 years ago
13

A proton is moved so that its electric potential energy increases from 4.0 × 10-14 J to 9.0 × 10-14 J. The magnitude of the char

ge on a proton is 1.602 × 10-19 C.
What is the electric potential difference through which the proton moved?

2.5 × 105 V
3.1 × 105 V
5.6 × 105 V
8.1 × 105 V
Physics
2 answers:
Kamila [148]2 years ago
8 0

Answer:

B. 3.1 × 10^5 V

Explanation:

masha68 [24]2 years ago
3 0

Answer:

B

Explanation:

e2021

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Which of these statements best describes how energy is transferred when an object experiences friction?
Slav-nsk [51]
<h2>Answer:</h2><h2> b hopefully this helps you with work </h2>
3 0
2 years ago
If you throw a ball down ward then acceleration immeditely after leaving your hand is
bezimeni [28]

Answer:

9.8m/s²

Explanation:

The acceleration of the ball thrown after leaving my hand is 9.8m/s². This will be the acceleration due to gravity on the body.

  • Acceleration due to gravity is caused by the pull of the earth on a massive object.
  • The value of this acceleration is 9.8m/s².
  • As the ball nears the surface, it comes near zero.
7 0
2 years ago
Suppose Joe, who can type 40 words per minute, takes 2.5 hours to type his report. To speed things up, his friend Mark offers to
Vika [28.1K]

Explanation:

When Joe works alone, the total number  of words he typed can be given by:

Total words = (40 words per minute) x (60 minutes per hour) x (2.5 hours)

Total words = 6000 words

Now, when Joe and Mark work together, let 'y' be the number of hours for which they both work simultaneously:

Total words = Words Typed by Joe + Words Typed by Mark

6000 = {(40 words per minute) x (60 minutes per hours) x (y hours)} + {(20 words per minute) x (60 minutes per hours) x (y hours)}

6000 = 2400y + 1200y = 3600y

y = 1.67 hours = 1 hour and 40 minutes

Thus, working together simultaneously, Joe and Mark will take 1 hour and 40 minutes to complete the report.

5 0
2 years ago
Sam is observing the velocity of a car at different times. After three hours, the velocity of the car is 53 km/h. After six hour
Serhud [2]
For the answer to the question above, first find out the gradient. 

<span>m = rise/run </span>
<span>=(y2-y1)/(x2-x1) </span>

<span>the x's and y's are the points given: "After three hours, the velocity of the car is 53 km/h. After six hours, the velocity of the car is 62 km/h" </span>
<span>(x1,y1) = (3,53) </span>
<span>(x2,y2) = (6,62) </span>

<span>sub values back into the equation </span>
<span>m = (62-53)/(6-3) </span>
<span>m = 9/3 </span>
<span>m = 3 </span>

<span>now we use a point-slope form to find the the standard form </span>
<span>y-y1 = m(x-x1) </span>
<span>where x1 and y1 are any set of point given </span>
<span>y-53 = 3(x-3) </span>
<span>y-53 = 3x - 9 </span>
<span>y = 3x - 9 + 53 </span>
<span>y = 3x + 44 </span>

<span>y is the velocity of the car, x is the time.
</span>I hope this helps.
4 0
3 years ago
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