Answer:
(a). $35746. (b). Higher.
Step-by-step explanation:
(a). Given that the least-squares regression equation is y = 7163x + 14242. Also, in the question above we are given that y is the median income and x is the percentage of 25 years and older with at least a bachelor's degree in the region, that is to say that the value of x = 30.
Therefore, y = 7163x + 14242.
y = (7163 × 30) + 14242.
y = $35746.
(b). The condition for our x is; 28.7 percent of adults 25 years and older have at least a bachelor's degree.
Then, y = (7163 × 28.7) + 14242.
y = $34814.
Hence, we have the median income in this region = $38,163 HIGHER than $34814.
Answer:
You can use either of the following to find "a":
- Pythagorean theorem
- Law of Cosines
Step-by-step explanation:
It looks like you have an isosceles trapezoid with one base 12.6 ft and a height of 15 ft.
I find it reasonably convenient to find the length of x using the sine of the 70° angle:
x = (15 ft)/sin(70°)
x ≈ 15.96 ft
That is not what you asked, but this value is sufficiently different from what is marked on your diagram, that I thought it might be helpful.
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Consider the diagram below. The relation between DE and AE can be written as ...
DE/AE = tan(70°)
AE = DE/tan(70°) = DE·tan(20°)
AE = 15·tan(20°) ≈ 5.459554
Then the length EC is ...
EC = AC - AE
EC = 6.3 - DE·tan(20°) ≈ 0.840446
Now, we can find DC using the Pythagorean theorem:
DC² = DE² + EC²
DC = √(15² +0.840446²) ≈ 15.023527
a ≈ 15.02 ft
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You can also make use of the Law of Cosines and the lengths x=AD and AC to find "a". (Do not round intermediate values from calculations.)
DC² = AD² + AC² - 2·AD·AC·cos(A)
a² = x² +6.3² -2·6.3x·cos(70°) ≈ 225.70635
a = √225.70635 ≈ 15.0235 . . . feet
Answer:
5:5 (first box, pencils to pens)
7:3 (second box, coloured pencils to crayons)
The probability of picking a pen (1st box): 5/10
The probability of picking a crayon (2nd box): 3/10
Probability of picking both: 5/10*3/10 = 15/100
The point-slope form of the equation of a straight line is:

We have:

Substitute:

Sixty-nine thousand, a hundred and eight?