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Aleksandr [31]
3 years ago
6

The TI-83/84 Plus calculator can be used to generate random data from a normally distributed population. The command randNorm(10

0,15,50) generates 50 values from a normally distributed population with and . One such generated sample of 50 values has a mean of 98.4 and a SD of 16.3. Assume that is known to be 15. Estimate the mean value from the random number generator using 99% confidence
Mathematics
1 answer:
postnew [5]3 years ago
3 0

Answer:

99% confidence interval for the mean value from the random number generator is a lower limit of 85.87 and an upper limit of 110.93.

Step-by-step explanation:

Confidence interval = mean +/- margin of error (E)

mean = 98.4

sd = 16.3

n = 15

degree of freedom (df) = n - 1 = 15 - 1 = 14

confidence level (C) = 99% = 0.99

significance level = 1 - C = 1 - 0.99 = 0.01 = 1%

t-value corresponding to 14 df and 1% significance level is 2.977.

E = t×sd/√n = 2.977×16.3/√15 = 12.53

Lower limit = mean - E = 98.4 - 12.53 = 85.87

Upper limit = mean + E = 98.4 + 12.53 = 110.93

99% confidence interval for the mean is between 85.87 and 110.93

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Find the slope and the y-intercept of the graph of the linear equation. 1. y=3x-7 2. y-1=-2/3x
ELEN [110]

Answer:

1) Slope: 3; y-intercept: -7

2) Slope: 2/3; y-intercept: 1

Step-by-step explanation:

y = mx + b; m is slope and b is y-intercept

1. y = 3x - 7

The equation is already in slope-intercept form, so you can find the slope and intercept.

Slope: 3

y-intercept: -7

2. y - 1 = 2/3x

For this one, you have to convert this into slope-intercept form (solving for y)

y - 1 = 2/3x

Add 1 to both sides

y - 1 + 1 = 2/3x + 1

y = 2/3x + 1

Now that the equation is in slope-intercept form, you can get the slope and y-intercept.

Slope: 2/3

y-intercept: 1

5 0
3 years ago
Question is attached.
Ratling [72]
The answers are m=2 and b=1 
7 0
3 years ago
Solve the system of equations using substitution:<br><br> 7y+2x=16 <br> 5y-9=x
7nadin3 [17]
7y+2(5y-9)=16
7y+10y-18=16
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5 0
3 years ago
A park bench is located 73 1/2 feet away from the basketball court. The pond which is located between the two is 25 3/8 feet awa
grigory [225]

Answer:

The pond is located  48\frac{1}{8}\ feet  away from the park bench.

Step-by-step explanation:

Given:

A park bench is located 73 1/2 feet away from the basketball court. The pond which is located between the two is 25 3/8 feet away from the basketball court.

Now, to find the distance the park bench from the pond.

<em>The distance park bench is located away from the basketball court</em> = 73\frac{1}{2}\ feet=\frac{147}{2} \ feet.

<u><em>As, the pond is located between the park bench and the basketball court.</em></u>

<em>The distance pond is located away from the basketball court</em> = 25\frac{3}{8}=\frac{203}{8}\ feet.

Now, to get the distance far away the pond is located from the park bench by subtracting the distance pond is located away from the basketball court from the distance park bench is located away from the basketball court:

\frac{147}{2}-\frac{203}{8}

=\frac{588-203}{8}

=\frac{385}{8}

=48\frac{1}{8} \ feet.

Therefore, the pond is located  48\frac{1}{8}\ feet  away from the park bench.

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3 years ago
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