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Nostrana [21]
3 years ago
7

A physicist is investigating a beam of laser light of wavelength 550 nm. The light strikes a target that is 189 meters away from

the source of the light. What is the travel time of the light from the source to the target? Let the speed of light c = 3.00 × 10^8 m/s.
Physics
1 answer:
Lena [83]3 years ago
8 0

Answer: here you go I was looking for this answer everywhere,I have it now so it’s 6.30 x 10^-7 s

Explanation:

I hope this helps☺️

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A rubber ball with a mass 0.20 kg is dropped vertically from a height of 1.5 m above the floor. The ball bounces off of the floo
Digiron [165]
Potential Energy = mass * Hight * acceleration of gravity
PE=hmg
PE = 1.5 * .2 * 9.81
PE = 2.943
it lost .6 so 2.943 - .6 = 2.343
now your new energy is 2.343 so solve for height
2.343 = mhg
2.334 = .2 * h * 9.81
h = 1.194
the ball after the bounce only went up 1.194m
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3 years ago
How do you calculate leap years?
Vadim26 [7]
Every 4 years is a leap year 2016 is a leap year and so is 2020
8 0
4 years ago
How do i solve A sound wave has a frequency of 658 Hz in air
kiruha [24]

Answer:

-47 °C

Explanation:

Speed of sound in air at sea level is:

v = 331 m/s + 0.6 m/s/°C T

where T is the temperature in Celsius.

The speed of sound is also the frequency times the wavelength:

v = fλ

Therefore:

fλ = 331 m/s + 0.6 m/s/°C T

(658 Hz) (0.46 m) = 331 m/s + 0.6 m/s/°C T

302.68 m/s = 331 m/s + 0.6 m/s/°C T

-28.32 m/s = 0.6 m/s/°C T

T = -47.2 °C

Rounding to two significant figures, the temperature is -47 °C.

6 0
3 years ago
What would be the best method to separate only iron fillings from a mixture of sand, water, iron filings, and salt
IrinaVladis [17]
Use a magnet idk the details hope this helps

8 0
3 years ago
Read 2 more answers
A golf ball (mass 0.045 kg) is hit with a club from a tee. The plot shows the force on the ball as a function of time in millise
almond37 [142]

Answer:

16.3 m/s

Explanation:

We are given that

Mass of golf ball=m=0.045 kg

We have to find the speed right after the hit.

b_1=(16-1)\times 10^{-3}=15\times 10^{-3} s

b_2=(12-6)\times 10^{-3}=6\times 10^{-3} s

Force,F=70 N

Change in momentum=Area of trapezium

Area of trapezium,A=\frac{1}{2}(b_1+b_2) h

Using the formula

m(v-u)=\frac{1}{2}(15+6)\times 10^{-3}\times 70

0.045(v-u)=\frac{1}{2}(21)\times 10^{-3}\times 70

v-u=\frac{1}{2}\times \frac{1}{0.045}\times 21\times 10^{-3}\times 70

v-u=16.3

Initial velocity of golf ball=u=0

v-0=16.3

v=16.3 m/s

5 0
3 years ago
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