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Verdich [7]
2 years ago
9

A 20 ohm lamp and a 5 ohm lamp are connected in series and placed across a potential difference of 50 V.

Physics
1 answer:
iogann1982 [59]2 years ago
7 0

Hi there!

1.

Since the two resistors are in series, we can simply add:
R_T = R_1 + R_2 + ... R_n

R_T = 20 + 5 = \boxed{25 \Omega}

2.

In series, the potential difference of each resistor (lamp) ADDS UP. We can begin by finding the current through the circuit using Ohm's law:
V = IR\\\\I = \frac{V}{R_T}

Plug in the values:
I = \frac{50}{25} = 2 A

Now,

we can use Ohm's law to find the individual voltage for each lamp.

20 Ohm lamp:
V = 2 * 20 = \boxed{40 V}

5 Ohm lamp:
V = 2 * 5 = \boxed{10 V}

3.

To solve, we can use the power equation.

P (\text{Watts})= IV

Plug in the values for each.

20 Ohm lamp:
P = 2 * 40 = \boxed{80 W}

5 Ohm lamp:
P = 2 * 10 = \boxed{100 W}

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Answer:

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Therefore, moment of inertia will be

\frac {240\times 25^{3}}{12}+(240\times 25)\times (56.25-25/2)^{2}+2\times [\frac {20\times 150^{3}}{12}+(20\times 150)\times ((25+150/2)-56.25)^{2}]=34.5313\times 10^{6} mm^{4}}

Bending stress at top= \frac {630\times 10^{3}\times (175-56.25)}{34.5313\times 10^{6}}=2.1665127\approx 2.17 Mpa

Bending stress at bottom=\frac {630\times 10^{3}\times 56.25}{34.5313\times 10^{6}}=1.026242858\approx 1.03 Mpa

Comparing the two stresses, the maximum stress occurs at the bottom and is 2.17 Mpa

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.<br><img src="https://tex.z-dn.net/?f=25%20%7B%3F%7D%5E%7B%3F%7D%20%20%5Ctimes%20%5Cfrac%7B%3F%7D%7B%3F%7D%20" id="TexFormula1"
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Explanation:

Given that,

Initial speed of a car, u = 60 km/h = 16.67 m/s

Acceleration, a = 2m/s²

Final speed, v = 120 km/h = 33.33 m/s

We need to find the distance traveled and the time taken to make the distance.

acceleration = rate of change of velocity

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