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aleksley [76]
3 years ago
15

Mandy is testing an unknown solution to determine whether it is an acid or a base. She places a piece of red litmus paper into t

he solution and the paper turns blue. What is her unknown solution?
Physics
1 answer:
Marina CMI [18]3 years ago
5 0
The solution is a base
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Hooke's law describes a certain light spring of unstretched length 33.6 cm. when one end is attached to the top of a doorframe a
masha68 [24]
Missing question: "What is the spring's constant?"

Solution:
The object of mass m=6.89 kg exerts a force on the spring equal to its weight:
F=mg=(6.89 kg)(9.81 m/s^2)=67.6 N
When the object is attached to the spring, the displacement of the spring with respect to its equilibrium position is
\Delta x=43.2 cm-33.6 cm=9.6 cm=0.096 m
And by using Hook's law, we can find the constant of the spring:
k= \frac{F}{\Delta x}= \frac{67.6 N}{0.096 m}=704.2 N/m
4 0
3 years ago
What type of tide occurs on a full moon or a new moon?
DIA [1.3K]
Spring tides will occur during a full moon and an new moon. The sun and moon are on a certain angle causing these tides to be neap tides, they aren't high tide nor are they low tides so you would verbalize they are in between and that is why it is called neap tides as well.
6 0
3 years ago
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You push a bike pedal 10cm and the bike moves 100cm. Calculate the Speed ratio ( show all work ) ( use the formula and divide th
scZoUnD [109]

Answer:

when you are pushing the pedal you are causing the pedal to move done and then you will move 100cm

Explanation:

10 cm= 100 cm moved so when you move you will move because you are timeing  the 10 by 100 to get the spped

3 0
3 years ago
We need to find the launch velocity of our new marble launcher. we know that it will launch a 25g marble to a distance of 73 cm,
White raven [17]

The launch velocity of the marble launcher is 34.65 m/s

Given that the launch velocity of marble launcher, launches a 25g marble to a distance of 73 cm (0.73 m) and the marble roll up to 6.2 meters before stopping. The launch height is 20 cm (0.2 m).

The time for landing can be calculated by the second equation of motion formula:

h = ut + \frac{1}{2}gt^{2}

Let u = 0

0.2 = 0×t + \frac{1}{2} × 9.8 × t^{2}

t^{2} = \frac{0.2}{4.9}

t^{2} = 0.04

t = 0.2s

Now, the launch velocity of the marble launcher can be calculated by:

Speed = Distance / Time

Speed = \frac{0.73 + 6.3}{0.2}

Speed = \frac{6.93}{0.2}

Speed = 34.65 m/s

Therefore, the launch velocity of the marble launcher is 34.65 m/s

Know more about Launch velocity: -brainly.com/question/18883779

#SPJ9

3 0
1 year ago
What property of matter do we consider when deciding whether to buy a half-gallon of milk at the store versus a gallon of milk?
Mrac [35]
Liquified matter maybe.
7 0
3 years ago
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