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2 years ago

Hi gir_ls join nkd-mbja-nuj

Physics

1 answer:

GREYUIT [131]2 years ago

3 0

Answer:

never lol

studying is your work

but why all are doing I don't know=_=

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Be sure to answer all parts. Compare the wavelengths of an electron (mass = 9.11 × 10−31 kg) and a proton (mass = 1.67 × 10−27 k

Harrizon [31]

Explanation:

Given that,

(a) Speed, $v=6.66\times 10^6\ m/s$

Mass of the electron, $m_e=9.11\times 10^{-31}\ kg$

Mass of the proton, $m_p=1.67\times 10^{-27}\ kg$

The wavelength of the electron is given by :

$\lambda_e=\dfrac{h}{m_ev}$

$\lambda_e=\dfrac{6.63\times 10^{-34}}{9.11\times 10^{-31}\times 6.66\times 10^6}$

$\lambda_e=1.09\times 10^{-10}\ m$

The wavelength of the proton is given by :

$\lambda_p=\dfrac{h}{m_p v}$

$\lambda_p=\dfrac{6.63\times 10^{-34}}{1.67\times 10^{-27}\times 6.66\times 10^6}$

$\lambda_p=5.96\times 10^{-14}\ m$

(b) Kinetic energy, $K=1.71\times 10^{-15}\ J$

The relation between the kinetic energy and the wavelength is given by :

$\lambda_e=\dfrac{h}{\sqrt{2m_eK}}$

$\lambda_e=\dfrac{6.63\times 10^{-34}}{\sqrt{2\times 9.11\times 10^{-31}\times 1.71\times 10^{-15}}}$

$\lambda_e=1.18\times 10^{-11}\ m$

$\lambda_p=\dfrac{h}{\sqrt{2m_pK}}$

$\lambda_p=\dfrac{6.63\times 10^{-34}}{\sqrt{2\times 1.67\times 10^{-27}\times 1.71\times 10^{-15}}}$

$\lambda_p=2.77\times 10^{-13}\ m$

Hence, this is the required solution.

6 0

3 years ago

What is the amount of displacement of a runner who runs exactly 2 laps around a 400 meter track?

Alex787 [66]

Displacement is the distance and direction from the start point to the end point. Our runner finished exactly where he started. His displacement is zero.

5 0

3 years ago

Read 2 more answers

In the picture below, the candle is heating the water in the tank. Which picture shows how the water will move as it gets hot?

Masteriza [31]

The first picture, at the top, does.

5 0

2 years ago

Read 2 more answers

How far should the second antenna be moved in order to receive a minimum signal from a station that broadcasts at 99.4 MHz?

raketka [301]

Answer:

So the distance of the antenna from the station will be 3.018 m

Explanation:

We have given the frequency of the broadcast $f=99.4MHz=99.4\times 10^4Hz$

The speed of light $c=3\times 10^8m/sec$

The distance of the antenna to receive a minimum signal from the station is given by $d=\frac{v}{f}=\frac{3\times 10^{8}}{99.4\times 10^6}=3.018m$

So the distance of the antenna from the station will be 3.018 m

5 0

3 years ago

A 13,000-N vehicle is to be lifted by a 25-cm diameter hydraulic piston. What force needs to be applied to a 5.0 cm diameter pis

MaRussiya [10]

Answer:

Explanation:

We shall apply Pascal's Law in fluid mechanics

According to it , pressure is transmitted in liquid from one point to another without any change .

25 cm diameter = 12.5 x 10⁻² m radius

Area = 3.14 x (12.5 x 10⁻²)²

= 490.625 x 10⁻⁴ m²

Pressure by vehicle

Force / area

13000 / 490.625 x 10⁻⁴

= 26.497 x 10⁴ Pa

5 cm diameter = 2.5 x 10⁻² radius

area = 3.14 x (2.5 x 10⁻²)²

= 19.625 x 10⁻⁴ m²

If we assume required force F on this area

Pressure = F / 19.625 x 10⁻⁴ Pa

According to Pascal Law

F / 19.625 x 10⁻⁴ = 26.497 x 10⁴

F = 19.625 x 26.497

= 520 N

4 0

3 years ago

Hi gir_ls join nkd-mbja-nuj​

Hi gir_ls join nkd-mbja-nuj