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Trava [24]
3 years ago
13

Which level of classification contains all the others?

Biology
1 answer:
solniwko [45]3 years ago
6 0

Answer:

The answer is Kingdom .

Explanation:

Kingdom is place the highest in the level of classification .

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Where is the cell body for the preganglionic neuron found?
slava [35]

Answer:

Location of the Cell Bodies Also, the cell bodies of the preganglionic neuron are located in the brain or spinal cord while the cell bodies of the postganglionic neuron are located in the ganglion. Axons of Preganglionic and Postganglionic Neurons

3 0
3 years ago
Complete the sentence. Stephen Crane was both a novelist and a _____.
DerKrebs [107]
Stephen Crane was both a novelist and a C. reporter, although he left that other job and became a full time writer. 
8 0
3 years ago
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Name at least four critters that might be pollinators
Elenna [48]
Four critters that are pollinators are
- Bumblebee
- Honeybee
- Rufous Hummingbird
- Flower fly
Hope this helps!
3 0
3 years ago
Calculate the final concentration of BSA in the problems below using the formula
Rudiy27

Answer:

A. C_2=1.5\frac{mg}{mL}

B. C_2=0.075\frac{mg}{mL}

C. C_2=0.01\frac{mg}{mL}

D. C_2=0.001\frac{mg}{mL}

Explanation:

Hello.

In this case, we must compute the final concentration in all the cases so we solve for it in the given equation:

C_2=\frac{C_1V_1}{V_2}

Thus, we proceed as follows:

A. Here, the final diluted solution includes the 300 μL of the 5 mg/ml-BSA and the 700 μL of TBS.

C_2=\frac{300\mu L*5\frac{mg}{mL} }{(300+700)\mu L}\\\\C_2=1.5\frac{mg}{mL}

B. Here, the final diluted solution includes the 50 μL of the 1.5 mg/ml-BSA, the 450 μL of water and the 500 μL of TBS.

C_2=\frac{50\mu L*1.5\frac{mg}{mL} }{(50+450+500)\mu L}\\\\C_2=0.075\frac{mg}{mL}

C. Here, the final diluted solution includes the 10 μL of the 1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.01\frac{mg}{mL}

D. Here, the final diluted solution includes the 10 μL of the 0.1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*0.1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.001\frac{mg}{mL}

Best regards.

7 0
3 years ago
The number of possible genetically different gametes for an organism equals
masya89 [10]

The organism can produce 12 genetically different gametes.

<h3><u>Explanation:</u></h3>

The gametes are the unit of sexual reproduction which are produced by an organism from their germ mother cell by means of meiosis. This gametes do carry half the amount of total chromosomes that is present inside each cell of that organism. This process let's the genetic combinations of chromosomes to get more variations among offsprings. But this isn't the only source of variation among the offsprings.

Each and every germ mother cell that's undergoing the meiotic division undergoes a process called crossing over and chaismata formation which gives the genetic mixing among the different alleles of same character among the organism.

Thus, statistically, if the organism has n pairs of chromosomes, then the organism will be able to produce 2n number of genetically different gametes which helps in finding out the probability of genotype of the offsprings.

So if the organism has 6 pairs of chromosomes, then the organism will be able to produce 12 genetically different gametes.

3 0
4 years ago
Read 2 more answers
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