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2 years ago

Can someone please help me?

Mathematics

2 answers:

Bingel [31]2 years ago

8 0

So the right answer is 29.

Look at the attached picture

Hope it will help you....

Good luck on your assignment

~pragya

Morgarella [4.7K]2 years ago

6 0

Answer:

x = 29

Step-by-step explanation:

As per image:

Sum of all the angles = 90 degree

$(x+3)\degree+(x-1)\degree+(x+1)\degree= 90\degree\\(3x+3)\degree= 90\degree\\3x+3= 90\\3x= 90-3\\3x= 87\\x=\frac{87}{3} \\x=29$

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Select the correct answer. Fredrick manages a band and sings lead vocals. The band charges $700 per concert. Fredrick receives $

Kisachek [45]

Answer:

A. $105

Step-by-step explanation:

Given

total charge= $700 per concert

solution

If Fredrick receives $175 of that money, the balance will be

$700-$175= $525

The balance will be shared by the 5 members

Hence each of them will take

525/5=$105

7 0

2 years ago

A store that buys and sells used video games buys a game at a cost of $9 and sells it at a selling price of $13. Find the mark

Bingel [31]

Markup = $4
b) markup as a percentage of cost is 33.3%
Step-by-step explanation:
Markup
markup = selling price - cost
= $13 - 9
... markup = $3
Markup as a Percentage of Cost
To find the percent markup, divide the markup by the reference value and multiply the ratio by 100%. The reference value for markup is usually cost price, but sometimes may be selling price.
... markup / cost × 100% = 3/9×100% = 33 1/3% ≈ 33.3%

4 0

2 years ago

Read 2 more answers

Hhelp pls lol i don't understand

sladkih [1.3K]

Answer:

m∠1= 80

m∠2= 100

m∠3= 80

Step-by-step explanation:

Given: m∠1= 2x +40

m∠2= 2y +40

m∠3= x +2y

m∠1 +m∠2= 180 (adj. ∠s on a str. line)

2x +40 +2y +40= 180

2x +2y+ 80= 180

2x +2y= 180 -80

2x +2y= 100

2(x +y)= 100

x +y= 100 ÷2

x +y= 50 -----(1)

m∠1= m∠3 (vert. opp. ∠s)

2x +40= x +2y

2x -x +40= 2y

x= 2y -40 -----(2)

Substitute equation (2) into (1):

2y -40 +y= 50

3y= 50 +40

3y= 90

y= 90 ÷3

y= 30

Substitute y= 30 into equation (2):

x= 2(30) -40

x= 60 -40

x= 20

m∠1

= 2x +40

= 2(20) +40

= 40 +40

= 80

m∠2

= 2y +40

= 2(30) +40

= 60 +40

= 100

m∠3

= x +2y

= 20 +2(30)

= 20 +60

= 80

Alternatively, since m∠1= m∠3,

m∠3

= m∠1 (vert. opp. ∠s)

= 80

5 0

2 years ago

. Write your answer in simplest form. 7/3 divided 9

Ymorist [56]

The answer is 7/27.......

5 0

2 years ago

Read 2 more answers

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

mash [69]

Answer:

The rocket hits the gorund after approximately 10.71 seconds.

Step-by-step explanation:

The height of the rocket y in feet x seconds after launch is given by the equation:

$y=-16x^2+165x+69$

And we want to find the time in which the rocket will hit the ground.

When it hits the ground, its height above ground will be 0. Hence, we can let y = 0 and solve for x:

$0=-16x^2+165x+69$

We can use the quadratic formula:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case, a = -16, b = 165, and c = 69.

Substitute:

$\displaystyle x=\frac{-165\pm\sqrt{(165)^2-4(-16)(69)}}{2(-16)}$

Evaluate:

$\displaystyle x=\frac{-165\pm\sqrt{31641}}{-32}=\frac{165\pm\sqrt{31641}}{32}$

Hence, our solutions are:

$\displaystyle x_1=\frac{165+\sqrt{31641}}{32}\approx 10.71\text{ or } x_2=\frac{165-\sqrt{31641}}{32}\approx-0.40$

Since time cannot be negative, we can ignore the first answer.

So, the rocket hits the gorund after approximately 10.71 seconds.

7 0

2 years ago